'How to display current logged-in user's information in all templates including view managed by WebMvcConfigurerAdapter in Spring Security application
I have a Spring Boot application that uses Spring Security and Thymeleaf template. I am trying to display the logged-in user's first name and last name in a template when the controller is managed by a subclass of WebConfigurerAdapter.
So, say my WebConfigurerAdapter subclass looks like this
@Configuration
public class MvcConfig extends WebMvcConfigurerAdapter{
@Override
public void addViewControllers(ViewControllerRegistry registry){
registry.addViewController("/some-logged-in-page").setViewName("some-logged-in-page");
registry.addViewController("/login").setViewName("login");
}
....
}
My User entity class looks like this
@Entity
@Table(name = "user")
public class User {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id", nullable = false, updatable = false)
private Long id;
@Column(name="first_name", nullable = false)
private String firstName;
public String getFirstName() {
return firstName;
}
...
}
In my template, I have tried using code like
<div sec:authentication="firstName"></div>
But it didn't work.
I know it is possible to use a ControllerAdvise as follows:
@ControllerAdvice
public class CurrentUserControllerAdvice {
@ModelAttribute("currentUser")
public UserDetails getCurrentUser(Authentication authentication) {
return (authentication == null) ? null : (UserDetails) authentication.getPrincipal();
}
}
and then access the details in the template using code like:
<span th:text ="${currentUser.getUser().getFirstName()}"></span>
But this doesn't work with any view controller registered with my class MvcConfig. Rather I will need to make sure each of my controllers are separate classes.
So, could someone kindly point me to a way to automatically insert the logged-in user details to my view, e.g. some-logged-in-page.html in this example? Thanks
Solution 1:[1]
It's quite easy to accomplish this, thanks to a hint from Balaji Krishnan.
Basically, I had to add the Thymeleaf Spring Security integration module to my build.gradle file as follows:
compile("org.thymeleaf.extras:thymeleaf-extras-springsecurity3")
Then in my template I just used the following markup:
<span th:text ="${#authentication.getPrincipal().getUser().getFirstName()}"></span>
Solution 2:[2]
When using Spring Security 4 and Thymeleaf 3:
<span th:text="${#authentication.getPrincipal().getUsername()}"></span>
Solution 3:[3]
When using Spring boot 2.2.1.
For the maven, Add these lines to the pom.xml
<dependency>
<groupId>org.thymeleaf.extras</groupId>
<artifactId>thymeleaf-extras-springsecurity5</artifactId>
</dependency>
In the thymeleaf
<span th:text="${#authentication.getPrincipal().getUsername()}"></span>
<span th:text="${#authentication.getPrincipal().authorities}"></span>
Solution 4:[4]
This construct is working for me (spring boot 1.5 and 2.0/thymeleaf 3):
It is documented here (bottom of the page) Thymeleaf + Spring Security integration basics
Logged user: <span sec:authentication="name">Bob</span>
Don“t forget to include the sec tag in the html section of your view:
<!DOCTYPE html>
<html xmlns:th="http://www.thymeleaf.org"
xmlns:sec="http://www.thymeleaf.org/extras/spring-security">
<head>
</head>
<body>
I hope this helps!
Have a nice day!
Thomas
Solution 5:[5]
As @B378 said, When using Spring Security 4 and Thymeleaf 3: you have to use following.
<span th:text="${#authentication.getPrincipal().getUsername()}"></span>
Because spring security uses UserDetails internally. And UserDetails contains one function called getUsername().
Solution 6:[6]
For me, When using Spring boot 2.1.2 I need to use the following
<span th:text="${#authentication.getPrincipal()}"></span> <!-- No ".getUsername()"-->
With thymeleaf-extras-springsecurity5
Solution 7:[7]
This page was useful. Thanks for all the replies.
Please note that if you are using the latest Spring Boot i.e. version 2.1.0 then you need to use the following: thymeleaf-extras-springsecurity5
Solution 8:[8]
For thymleaf 4 and above you have to modify some classes in order to get the info. Heres how you can do that:
First, add the getter of your user getUser(){return this.user;} in the UserDetails class and then push that object in the UserDetailsService object. Without these changes, thymleaf will not parse your HTML file.
Then you can get the info as follows:
<span sec:authentication="principal.user.name">
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Dee |
| Solution 2 | B378 |
| Solution 3 | Nayan |
| Solution 4 | Thomas Lang |
| Solution 5 | Tanaji Kolekar |
| Solution 6 | user1145691 |
| Solution 7 | sunitkatkar |
| Solution 8 | Ullas Hunka |
