'How to display current logged-in user's information in all templates including view managed by WebMvcConfigurerAdapter in Spring Security application

I have a Spring Boot application that uses Spring Security and Thymeleaf template. I am trying to display the logged-in user's first name and last name in a template when the controller is managed by a subclass of WebConfigurerAdapter.

So, say my WebConfigurerAdapter subclass looks like this

@Configuration
public class MvcConfig extends WebMvcConfigurerAdapter{

    @Override
    public void addViewControllers(ViewControllerRegistry registry){
        registry.addViewController("/some-logged-in-page").setViewName("some-logged-in-page");
        registry.addViewController("/login").setViewName("login");

    }
    ....
}

My User entity class looks like this

@Entity
@Table(name = "user")
public class User {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id", nullable = false, updatable = false)
    private Long id;



    @Column(name="first_name", nullable = false)
    private String firstName;


    public String getFirstName() {
        return firstName;
    }
    ...
}

In my template, I have tried using code like

<div sec:authentication="firstName"></div> 

But it didn't work.

I know it is possible to use a ControllerAdvise as follows:

@ControllerAdvice
public class CurrentUserControllerAdvice {
    @ModelAttribute("currentUser")
    public UserDetails getCurrentUser(Authentication authentication) {
        return (authentication == null) ? null : (UserDetails) authentication.getPrincipal();
    }
}

and then access the details in the template using code like:

<span th:text ="${currentUser.getUser().getFirstName()}"></span>

But this doesn't work with any view controller registered with my class MvcConfig. Rather I will need to make sure each of my controllers are separate classes.

So, could someone kindly point me to a way to automatically insert the logged-in user details to my view, e.g. some-logged-in-page.html in this example? Thanks



Solution 1:[1]

It's quite easy to accomplish this, thanks to a hint from Balaji Krishnan.

Basically, I had to add the Thymeleaf Spring Security integration module to my build.gradle file as follows:

compile("org.thymeleaf.extras:thymeleaf-extras-springsecurity3")

Then in my template I just used the following markup:

<span th:text ="${#authentication.getPrincipal().getUser().getFirstName()}"></span>

Solution 2:[2]

When using Spring Security 4 and Thymeleaf 3:

<span th:text="${#authentication.getPrincipal().getUsername()}"></span>

Solution 3:[3]

When using Spring boot 2.2.1.

For the maven, Add these lines to the pom.xml

<dependency>
    <groupId>org.thymeleaf.extras</groupId>
    <artifactId>thymeleaf-extras-springsecurity5</artifactId>
</dependency>

In the thymeleaf

<span th:text="${#authentication.getPrincipal().getUsername()}"></span>
<span th:text="${#authentication.getPrincipal().authorities}"></span>

Solution 4:[4]

This construct is working for me (spring boot 1.5 and 2.0/thymeleaf 3):
It is documented here (bottom of the page) Thymeleaf + Spring Security integration basics

Logged user: <span sec:authentication="name">Bob</span>

Don“t forget to include the sec tag in the html section of your view:

<!DOCTYPE html>
<html xmlns:th="http://www.thymeleaf.org"
      xmlns:sec="http://www.thymeleaf.org/extras/spring-security">
<head>
</head>
<body>

I hope this helps!
Have a nice day!
Thomas

Solution 5:[5]

As @B378 said, When using Spring Security 4 and Thymeleaf 3: you have to use following.

<span th:text="${#authentication.getPrincipal().getUsername()}"></span>

Because spring security uses UserDetails internally. And UserDetails contains one function called getUsername().

Solution 6:[6]

For me, When using Spring boot 2.1.2 I need to use the following

<span th:text="${#authentication.getPrincipal()}"></span> <!-- No ".getUsername()"-->

With thymeleaf-extras-springsecurity5

Solution 7:[7]

This page was useful. Thanks for all the replies. Please note that if you are using the latest Spring Boot i.e. version 2.1.0 then you need to use the following: thymeleaf-extras-springsecurity5

LINK

Solution 8:[8]

For thymleaf 4 and above you have to modify some classes in order to get the info. Heres how you can do that:

First, add the getter of your user getUser(){return this.user;} in the UserDetails class and then push that object in the UserDetailsService object. Without these changes, thymleaf will not parse your HTML file.

Then you can get the info as follows:

<span sec:authentication="principal.user.name">

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 Dee
Solution 2 B378
Solution 3 Nayan
Solution 4 Thomas Lang
Solution 5 Tanaji Kolekar
Solution 6 user1145691
Solution 7 sunitkatkar
Solution 8 Ullas Hunka