How to make discord bot disconnect from voice channel after playing?

Question

I'm trying to get the discord bot to disconnect from the voice channel after it finishes playing, but I can't use "await" in a lambda expression.

I tried it:

voice_client.play(source=audio_source, after=lambda _: await voice_client.disconnect())

But the result is:

SyntaxError: 'await' outside async function

I tried it:

voice_client.play(source=audio_source, after=lambda _: voice_client.disconnect())

But the result is:

RuntimeWarning: coroutine 'VoiceClient.disconnect' was never awaited self.after(error)

I tried it:

voice_client.play(source=audio_source, after=voice_client.disconnect)

But the result is:

TypeError: disconnect() takes 1 positional argument but 2 were given

My solution:

voice_client.play(
    source=audio_source,
    after=lambda _: asyncio.run_coroutine_threadsafe(
        coro=voice_client.disconnect(),
        loop=voice_client.loop
    ).result()
)

Answer 1

RuntimeWarning: coroutine 'VoiceClient.disconnect' was never awaited self.after(error)

VoiceClient need to add await in front of it. This function is a coroutine.

voice_client.play(source=audio_source, after=lambda _: await voice_client.disconnect())

After that you will meet this error

SyntaxError: 'await' outside async function

You cant use await outside async function

async def func(): #must add async here
    await func2()

Try to add async at the function of your music command.

@bot.commands() #i dont know what type of command you are using, it also can be cogs or slash command
async def yourcommand(args): #add `async` in front `def`
    #your code.....
    voice_client.play(source=audio_source, after=lambda _: await voice_client.disconnect())