How I replace a string in a list that contain int and float? in python

Question

I am trying to clean a database. I am extracting each column and cleaning separately with this formula:

def Cleaning_strings(Data,Correction):
    for i in range(len(Data)):
        if isinstance(Data[i], float) : 
            Mom_Normal = Data[i]
            Correction.append(Mom_Normal)
        elif isinstance(Data[i], int): 
            Mom_Normal1 = Data[i]
            Correction.append(Mom_Normal1)
        else:
            Zeros = int(Data[i].replace('--','0')) 
            Correction.append(Zeros)

For example, if i have a series (which I extracted before like this : df['Name of the column']) like this: Data = [4.0,5,3.4,'--'] the code work perfectly but if I have the data like this Data =[4.0,5,3.4,'--','1.45k'] it does not work.

I'm trying to change the code like this:

def Cleaning_strings(Data,Correction):
    for i in range(len(Data)):
        if isinstance(Data[i], float) : #Como cada dato se considera 
            Mom_Normal = Data[i]
            Correction.append(Mom_Normal)
        elif isinstance(Data[i], int): 
            Mom_Normal1 = Data[i]
            Correction.append(Mom_Normal1)
        elif isinstance(Data[i], str):
            Thousands = int(Data[i].replace('k',''))*1000
            Correction.append(Thousands)
        else:
            Zeros = int(Data[i].replace('--','0')) #No hay dato
            Correction.append(Zeros)

and the error that appears is:

ValueError: invalid literal for int() with base 10: '--'

I understand why I get this error, but what I don't know is how I can modify the formula to make it work on this data. Please help me to find the way to replace the 'k' of the data.