'How can I hide/show components by touching not button but screen on React Native?
I'm learning React Native for the first time. I want to implement a function to show/hide the component by touching the screen, not a specific button.
(Please check the attached file for the example image.)
In this code, I've tried to make a function. if I touch the screen (<View style={style.center}>, then show/hide the renderChatGroup() and renderListMessages() included in <View style={style.footer}>. The source code is below.
In my code, it works. However, the two <View> tag is not parallel. the footer view is center View's child.
I want to make them parallel. but I couldn't find the contents about controlling another <View> tag, not a child. In this code, I used setState, then I couldn't control another the below <View>.
Of course, I tried Fragment tag, but it didn't render anything.
How could I do implement this function? Please help me!
export default class Streamer extends React.Component {
constructor(props) {
super(props);
this.state = {
isVisibleFooter: true,
};
}
renderChatGroup = () => {
const { isVisibleFooter } = this.state;
if (isVisibleFooter) {
return (
<ChatInputGroup
onPressHeart={this.onPressHeart}
onPressSend={this.onPressSend}
onFocus={this.onFocusChatGroup}
onEndEditing={this.onEndEditing}
/>
);
}
return null;
};
onPressVisible = () => {
const { isVisibleFooter } = this.state;
this.setState(() => ({ isVisibleFooter: !isVisibleFooter }));
};
render() {
return (
<SafeAreaView style={styles.container}>
<SafeAreaView style={styles.contentWrapper}>
<View style={styles.header} />
<TouchableWithoutFeedback onPress={this.onPressVisible}>
<View style={styles.center}>
<View style={styles.footer}>
{this.renderChatGroup()}
{this.renderListMessages()}
</View>
</View>
</TouchableWithoutFeedback>
</SafeAreaView>
</SafeAreaView>
);
}
}
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
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