'React: Passing down props to functional components
I have a seemingly trivial question about props and functional components. Basically, I have a container component which renders a Modal component upon state change which is triggered by user click on a button. The modal is a stateless functional component that houses some input fields which need to connect to functions living inside the container component.
My question: How can I use the functions living inside the parent component to change state while the user is interacting with form fields inside the stateless Modal component? Am I passing down props incorrectly? Thanks in advance.
Container
export default class LookupForm extends Component {
constructor(props) {
super(props);
this.state = {
showModal: false
};
}
render() {
let close = () => this.setState({ showModal: false });
return (
... // other JSX syntax
<CreateProfile fields={this.props} show={this.state.showModal} onHide={close} />
);
}
firstNameChange(e) {
Actions.firstNameChange(e.target.value);
}
};
Functional (Modal) Component
const CreateProfile = ({ fields }) => {
console.log(fields);
return (
... // other JSX syntax
<Modal.Body>
<Panel>
<div className="entry-form">
<FormGroup>
<ControlLabel>First Name</ControlLabel>
<FormControl type="text"
onChange={fields.firstNameChange} placeholder="Jane"
/>
</FormGroup>
);
};
Example: say I want to call this.firstNameChange from within the Modal component. I guess the "destructuring" syntax of passing props to a functional component has got me a bit confused. i.e:
const SomeComponent = ({ someProps }) = > { // ... };
Solution 1:[1]
You would need to pass down each prop individually for each function that you needed to call
<CreateProfile
onFirstNameChange={this.firstNameChange}
onHide={close}
show={this.state.showModal}
/>
and then in the CreateProfile component you can either do
const CreateProfile = ({onFirstNameChange, onHide, show }) => {...}
with destructuring it will assign the matching property names/values to the passed in variables. The names just have to match with the properties
or just do
const CreateProfile = (props) => {...}
and in each place call props.onHide or whatever prop you are trying to access.
Solution 2:[2]
I'm using react function component
In parent component first pass the props like below shown
import React, { useState } from 'react';
import './App.css';
import Todo from './components/Todo'
function App() {
const [todos, setTodos] = useState([
{
id: 1,
title: 'This is first list'
},
{
id: 2,
title: 'This is second list'
},
{
id: 3,
title: 'This is third list'
},
]);
return (
<div className="App">
<h1></h1>
<Todo todos={todos}/> //This is how i'm passing props in parent component
</div>
);
}
export default App;
Then use the props in child component like below shown
function Todo(props) {
return (
<div>
{props.todos.map(todo => { // using props in child component and looping
return (
<h1>{todo.title}</h1>
)
})}
</div>
);
}
Solution 3:[3]
An addition to the above answer.
If React complains about any of your passed props being undefined, then you will need to destructure those props with default values (common if passing functions, arrays or object literals) e.g.
const CreateProfile = ({
// defined as a default function
onFirstNameChange = f => f,
onHide,
// set default as `false` since it's the passed value
show = false
}) => {...}
Solution 4:[4]
just do this on source component
<MyDocument selectedQuestionData = {this.state.selectedQuestionAnswer} />
then do this on destination component
const MyDocument = (props) => (
console.log(props.selectedQuestionData)
);
Solution 5:[5]
A variation of finalfreq's answer
You can pass some props individually and all parent props if you really want (not recommended, but sometimes convenient)
<CreateProfile
{...this.props}
show={this.state.showModal}
/>
and then in the CreateProfile component you can just do
const CreateProfile = (props) => {
and destruct props individually
const {onFirstNameChange, onHide, show }=props;
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Community |
| Solution 2 | MwamiTovi |
| Solution 3 | MwamiTovi |
| Solution 4 | Krishna Jangid |
| Solution 5 |
