Write a program that first takes in word pairs that consist of a name and a phone number (both strings), separated by a comma

Question

I have the following prompt:

A contact list is a place where you can store a specific contact with other associated information such as a phone number, email address, birthday, etc. Write a program that first takes in word pairs that consist of a name and a phone number (both strings), separated by a comma. That list is followed by a name, and your program should output the phone number associated with that name. Assume the search name is always in the list.

Ex:

If the input is: Joe,123-5432 Linda,983-4123 Frank,867-5309 Frank the output is: 867-5309

my code:

pn = str(input()).split()

search = str(input())

i=0

for i in range(len(on)):

if pn[i] == (search):

print([i+1])

The input is getting split into a name and number. When the code goes to check if the names are the same, it always returns false. I've tried using the re.split() method, but it didn't work.

Answer 1

You should split twice and second split char should be a comma s.split(",")

s = "Joe,123-5432 Linda,983-4123 Frank,867-5309"

for i in s.split():
    temp = i.split(",");
    print("name :", temp[0] , " number is :" , temp[1] )

Output

name : Joe  number is : 123-5432
name : Linda  number is : 983-4123
name : Frank  number is : 867-5309

Answer 2

Try splitting around the comma when searching for the name:

pn = input().split()
search = input()

for i in pn:
  val = i.split(',')
  if val[0] == search:
    print(val[1])

Answer 3

You need to have the following things in your program to meet the basic requirements

1. Infinite loop to enter contact info until user stop entering
2. List or Dictionary to hold entered info and for searching

The code can be like following

contacts = {}

while True:
    info = input('Enter Contact Info or Leave empty to Stop Entering: ').split(',')
    if len(info) > 1:
        contacts[info[0]] = info[1]
    else:
        break

name = input('Enter name to search: ')
print(contacts[name])

Output is following

Answer 4

It seems like you're trying to store the data as an input, ask the user for a query (name of a person), and then respond with that person's phone number.

# Get the data
inputs = input("Enter the input. >>> ").split(sep=" ")

# Split the data into lists
for pos in range(len(inputs)):
    inputs[pos] = inputs[pos].split(sep=",")

# Ask for a search query
query = input("Enter a name. >>> ")
# Check for the name in the first element of each item
for item in inputs:
    if item[0] == query:
        print(f"{query}'s phone number is {item[1]}.")
        break

A sample data input, as called in line 2:

Enter the input. >>> John,12313123 Bob,8712731823

As of the search query line of the code, your inputs variable looks something like: [['John', '12313123'], ['Bob', '8712731823']]. The program will iterate through the items of inputs, where each item is a list of two strings, and then check if the first item of this sub-list matches the inputted query.