'Using __file__ in script to get current file directory of script and executable file
I'm trying to write universal scripts that would work on any PC that meets requirements and I have a little problem with getting directories and paths right. Currently I have two folders in one location: C:\Users\myProject, one with my Scripts and other named Tests. In Scripts folder I store my python scripts with all instructions and in Tests I have .bat files used to execute scripts. To get parents path I decided to use (__file__), for example in my script - Test_Script.py:
__file__ = 'Test_Script.py'
print(r'__file__', __file__)
curr_path = os.path.dirname(os.path.abspath(__file__))
print (curr_path)
And it works, but in two ways. If I run cmd in folder with Scripts and type: py Test_Script.py, I get:
Test_Script.py
C:\Users\myProject\Scripts
But when I run it from Tests directory, I get:
Test_Script.py
C:\Windows\system32
How do I fix this to have same output as in first case while running script via cmd?
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