'using errors in conditions in python
I need help with my quadratic calculating program. I used an expression in an If, the expression will result in a math error obviously. But I don't want the code to break down when the error occurs instead, I want something else to happen.
import math
def quad(a, b, c):
# creating a variable for all the parts that make the expression
first_nu = int(a)
second_nu = int(b)
third_nu = int(c)
four = 4
two = 2
det = second_nu ** 2 - (four * (first_nu * third_nu))
if math.sqrt(det) == 0:
print(' the discriminant is 0 hence the quadratic has no real roots')
else:
# calculating the roots
root_det = math.sqrt(det)
def printing():
option1 = (-third_nu + root_det) / (two * first_nu)
option2 = (-third_nu - root_det) / (two * first_nu)
print(option1, option2)
if det < 0:
printing()
print('The roots are not real roots')
elif det == 0:
print('mathematical error in a situation where there is root of 0')
print('The roots has just one real root')
elif det > 0:
printing()
print('The roots has two real roots')
first_num = input("enter your first number of the quadratic")
second_num = input("enter your second number of the quadratic")
third_num = input("enter your third number of the quadratic")
quad(first_num, second_num, third_num)
Solution 1:[1]
Use try: on the code you want to test and put the rest of the code in except. I hope this will solve the issue. For more information about Python error handling here or check from w3schools
The try block lets you test a block of code for errors.
The except block lets you handle the error.
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Philip Mutua |
