unrecognized bytes python when convert overflow int to bytes

Question

I know how declare bytes I used to use hexadecimal notation like this

bita = b'\x01\x02'

I was trying run this simple code

overflow_int = 999999999999999999999999999999999999999999999999999999

bita= int.to_bytes(overflow_int,length=(overflow_int.bit_length()+7)//8,byteorder='big')

print(bita) 
print(len(bita))
print(bita[0])
print(b'\np'[0])
print(int.from_bytes(bita,byteorder='big'))

it gave me output

b'\np\xc3\xc4\nd\xe6\xc5\x19\x99\t\x0be\xf6}\x92?\xff\xff\xff\xff\xff\xff'
23
10
10
999999999999999999999999999999999999999999999999999999

In first index of bita, Yes I know why 10 because \n in ascii means newline which it's unprintable ascii and 10th ascii char.

But why b'\np' == b'\n'. Why it includes p? What does it means? Not only that but also symbol-symbol non-alpanumeric like ?{. Also why len(bita) == 23?