Spring caching behaviour in case of an error

Question

I have Spring Boot and cacheable method:

@Cacheable("ids")
 public List<String> getValidIds() {
        return list_from_another_service;
    }

I have the cache eviction config:

 @Scheduled(fixedRateString = "PT60M")
 @CacheEvict(value = "ids", allEntries = true)
 public void evictCache() {
        //Do nothing.
    }

Question: The cache is evicted each 1 hr. What should the cache return if getValidIds() method receives an error during cache refreshing? Will the cache be empty for 1 hour or will it still store and return the data from the previous successful call?

Answer 1

Using the Link will append the address link to your homepage.

See more of Link from React Router: https://v5.reactrouter.com/web/api/Link

You can do this to open the address in different tab.

 <button
  className="button"
  onClick={() => {
    window.open(btnLink);
  }}
>
  {btnText}
</button>

or if you want to open the address in the same tab.

<button
  className="button"
  onClick={() => {
    window.location.href = btnLink
  }}
>
  {btnText}
</button>

Answer 2

Using the Link component from react-router-dom will not work with external links that go away from your site URL. Something such as https://www.google.com will not work with that component. Instead, you will need to have an <a /> tag here and utilize the href attribute. You can simply style the <a /> tag link a button to get the behavior you are looking for once it is clicked. Here is a code example using a custom styled-component:

import React from 'react';
import styled from 'styled-components';

const LinkButtonComponent = styled.a`
    text-decoration: none !important;
    color: white;
    background-color: green;
    padding: 2px;
    border-radius: 3px;
    height: 50px;
    width: 100px;
    cursor: pointer;
`;

type LinkButtonProps = {
    children: React.ReactNode;
};

export default function LinkButton({ children }: LinkButtonProps) {
    return (
        <LinkButtonComponent href='https://www.google.com'>
            {children}
        </LinkButtonComponent>
    );
}