'Specify different filename for newplot.png in Dash dynamically
I am trying change the filename from the image file. I managed to change it from newplot.png to Plot.png, but I want to make it dynamically. In my app I added a drag & drop feature and I would like to use this filename as filename for the plot.
external_stylesheets = ['https://codepen.io/chriddyp/pen/bWLwgP.css']
app = dash.Dash(__name__, external_stylesheets=external_stylesheets)
server = app.server
app.layout = html.Div([
dcc.Upload(
id='upload-data',
children=html.Div([
'Drag and Drop or ',
html.A('Select Files')
]),
style={
'width': '80vh',
'height': '60px',
'lineHeight': '60px',
'borderWidth': '1px',
'borderStyle': 'dashed',
'borderRadius': '5px',
'textAlign': 'center',
'margin': '10px'
},
# Allow multiple files to be uploaded
multiple=True
),
dcc.Graph(id='Mygraph',
style={'width': '80vh', 'height': '50vh'},
config={'scrollZoom': True, 'toImageButtonOptions': {'filename': 'Plot'}}),
html.Br(),
dcc.Checklist(
id='relative_temperature',
options=['Relative']),
html.Br(),
dcc.Input(id='limit_line', type="number", value=45),
html.Br(),
html.Div(id='output-data-upload')
])
Solution 1:[1]
You can try this:
import sys
import dash
from dash import dcc
from dash import html
from dash.dependencies import Input, Output
import plotly.express as px
external_stylesheets = ['https://codepen.io/chriddyp/pen/bWLwgP.css']
app = dash.Dash(__name__, external_stylesheets=external_stylesheets)
app.layout = html.Div([
dcc.Upload(
id='upload-data',
children=html.Div([
'Drag and Drop or ',
html.A('Select Files')
]),
style={
'width': '80vh',
'height': '60px',
'lineHeight': '60px',
'borderWidth': '1px',
'borderStyle': 'dashed',
'borderRadius': '5px',
'textAlign': 'center',
'margin': '10px'
},
# Allow multiple files to be uploaded
multiple=True
),
html.Div(id='graph'),
html.Br(),
dcc.Checklist(
id='relative_temperature',
options=['Relative']),
html.Br(),
dcc.Input(id='limit_line', type="number", value=45),
html.Br(),
html.Div(id='output-data-upload')
])
@app.callback(Output('graph', 'children'),
[Input('upload-data', 'filename')])
def update_figure(name):
return dcc.Graph(id='Mygraph', style={'width': '80vh', 'height': '50vh'},
config={'scrollZoom': True, 'toImageButtonOptions': {'filename': name[-1].split('.')[0]}})
if __name__ == '__main__':
app.run_server(debug=False, use_reloader=False)
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | Phoenix |