'Sending live video frame over network in python opencv

I'm trying to send live video frame that I catch with my camera to a server and process them. I'm usig opencv for image processing and python for the language. Here is my code

client_cv.py

import cv2
import numpy as np
import socket
import sys
import pickle
cap=cv2.VideoCapture(0)
clientsocket=socket.socket(socket.AF_INET,socket.SOCK_STREAM)
clientsocket.connect(('localhost',8089))
while True:
    ret,frame=cap.read()
    print sys.getsizeof(frame)
    print frame
    clientsocket.send(pickle.dumps(frame))

server_cv.py

import socket
import sys
import cv2
import pickle
import numpy as np
HOST=''
PORT=8089

s=socket.socket(socket.AF_INET,socket.SOCK_STREAM)
print 'Socket created'

s.bind((HOST,PORT))
print 'Socket bind complete'
s.listen(10)
print 'Socket now listening'

conn,addr=s.accept()

while True:
    data=conn.recv(80)
    print sys.getsizeof(data)
    frame=pickle.loads(data)
    print frame
    cv2.imshow('frame',frame)

This code gives me end of file error, which is logical because the data always keep coming to the server and pickle doesn't know when to finish. My search on the internet made me use pickle but it doesn't work so far.

Note: I set conn.recv to 80 because that's the number I get when I say print sys.getsizeof(frame).

Solution 1:^[1]

Few things:

use sendall instead of send since you're not guaranteed everything will be sent in one go
pickle is ok for data serialization but you have to make a protocol of you own for the messages you exchange between the client and the server, this way you can know in advance the amount of data to read for unpickling (see below)
for recv you will get better performance if you receive big chunks, so replace 80 by 4096 or even more
beware of sys.getsizeof: it returns the size of the object in memory, which is not the same as the size (length) of the bytes to send over the network ; for a Python string the two values are not the same at all
be mindful of the size of the frame you are sending. Code below supports a frame up to 65535. Change "H" to "L" if you have a larger frame.

A protocol example:

client_cv.py

import cv2
import numpy as np
import socket
import sys
import pickle
import struct ### new code
cap=cv2.VideoCapture(0)
clientsocket=socket.socket(socket.AF_INET,socket.SOCK_STREAM)
clientsocket.connect(('localhost',8089))
while True:
    ret,frame=cap.read()
    data = pickle.dumps(frame) ### new code
    clientsocket.sendall(struct.pack("H", len(data))+data) ### new code

server_cv.py

import socket
import sys
import cv2
import pickle
import numpy as np
import struct ## new

HOST=''
PORT=8089

s=socket.socket(socket.AF_INET,socket.SOCK_STREAM)
print('Socket created')

s.bind((HOST,PORT))
print('Socket bind complete')
s.listen(10)
print('Socket now listening')

conn,addr=s.accept()

### new
data = ""
payload_size = struct.calcsize("H") 
while True:
    while len(data) < payload_size:
        data += conn.recv(4096)
    packed_msg_size = data[:payload_size]
    data = data[payload_size:]
    msg_size = struct.unpack("H", packed_msg_size)[0]
    while len(data) < msg_size:
        data += conn.recv(4096)
    frame_data = data[:msg_size]
    data = data[msg_size:]
    ###

    frame=pickle.loads(frame_data)
    print frame
    cv2.imshow('frame',frame)

You can probably optimize all this a lot (less copying, using the buffer interface, etc) but at least you can get the idea.

Solution 2:^[2]

After months of searching the internet, this is what I came up with, I have neatly packaged it into classes, with unit tests and documentation as SmoothStream check it out, it was the only simple and working version of streaming I could find anywhere.

I used this code and wrapped mine around it.

Viewer.py

import cv2
import zmq
import base64
import numpy as np

context = zmq.Context()
footage_socket = context.socket(zmq.SUB)
footage_socket.bind('tcp://*:5555')
footage_socket.setsockopt_string(zmq.SUBSCRIBE, np.unicode(''))

while True:
    try:
        frame = footage_socket.recv_string()
        img = base64.b64decode(frame)
        npimg = np.fromstring(img, dtype=np.uint8)
        source = cv2.imdecode(npimg, 1)
        cv2.imshow("Stream", source)
        cv2.waitKey(1)

    except KeyboardInterrupt:
        cv2.destroyAllWindows()
        break

Streamer.py

import base64
import cv2
import zmq

context = zmq.Context()
footage_socket = context.socket(zmq.PUB)
footage_socket.connect('tcp://localhost:5555')

camera = cv2.VideoCapture(0)  # init the camera

while True:
    try:
        grabbed, frame = camera.read()  # grab the current frame
        frame = cv2.resize(frame, (640, 480))  # resize the frame
        encoded, buffer = cv2.imencode('.jpg', frame)
        jpg_as_text = base64.b64encode(buffer)
        footage_socket.send(jpg_as_text)

    except KeyboardInterrupt:
        camera.release()
        cv2.destroyAllWindows()
        break

Solution 3:^[3]

I changed the code from @mguijarr to work with Python 3. Changes made to the code:

data is now a byte literal instead of a string literal
Changed "H" to "L" to send larger frame sizes. Based on the documentation, we can now send frames of size 2^32 instead of just 2^16.

Server.py

import pickle
import socket
import struct

import cv2

HOST = ''
PORT = 8089

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
print('Socket created')

s.bind((HOST, PORT))
print('Socket bind complete')
s.listen(10)
print('Socket now listening')

conn, addr = s.accept()

data = b'' ### CHANGED
payload_size = struct.calcsize("L") ### CHANGED

while True:

    # Retrieve message size
    while len(data) < payload_size:
        data += conn.recv(4096)

    packed_msg_size = data[:payload_size]
    data = data[payload_size:]
    msg_size = struct.unpack("L", packed_msg_size)[0] ### CHANGED

    # Retrieve all data based on message size
    while len(data) < msg_size:
        data += conn.recv(4096)

    frame_data = data[:msg_size]
    data = data[msg_size:]

    # Extract frame
    frame = pickle.loads(frame_data)

    # Display
    cv2.imshow('frame', frame)
    cv2.waitKey(1)

Client.py

import cv2
import numpy as np
import socket
import sys
import pickle
import struct

cap=cv2.VideoCapture(0)
clientsocket=socket.socket(socket.AF_INET,socket.SOCK_STREAM)
clientsocket.connect(('localhost',8089))

while True:
    ret,frame=cap.read()
    # Serialize frame
    data = pickle.dumps(frame)

    # Send message length first
    message_size = struct.pack("L", len(data)) ### CHANGED

    # Then data
    clientsocket.sendall(message_size + data)

Solution 4:^[4]

I'm kind of late but my powerful & threaded VidGear Video Processing python library now provide NetGear API, which is exclusively designed to transfer video frames synchronously between interconnecting systems over the network in real-time. Here's an example:

A. Server End:(Bare-Minimum example)

Open your favorite terminal and execute the following python code:

Note: You can end streaming anytime on both server and client side by pressing [Ctrl+c] on your keyboard on server end!

# import libraries
from vidgear.gears import VideoGear
from vidgear.gears import NetGear

stream = VideoGear(source='test.mp4').start() #Open any video stream
server = NetGear() #Define netgear server with default settings

# infinite loop until [Ctrl+C] is pressed
while True:
    try: 
        frame = stream.read()
        # read frames

        # check if frame is None
        if frame is None:
            #if True break the infinite loop
            break

        # do something with frame here

        # send frame to server
        server.send(frame)

    except KeyboardInterrupt:
        #break the infinite loop
        break

# safely close video stream
stream.stop()
# safely close server
writer.close()

B. Client End:(Bare-Minimum example)

Then open another terminal on the same system and execute the following python code and see the output:

# import libraries
from vidgear.gears import NetGear
import cv2

#define netgear client with `receive_mode = True` and default settings
client = NetGear(receive_mode = True)

# infinite loop
while True:
    # receive frames from network
    frame = client.recv()

    # check if frame is None
    if frame is None:
        #if True break the infinite loop
        break

    # do something with frame here

    # Show output window
    cv2.imshow("Output Frame", frame)

    key = cv2.waitKey(1) & 0xFF
    # check for 'q' key-press
    if key == ord("q"):
        #if 'q' key-pressed break out
        break

# close output window
cv2.destroyAllWindows()
# safely close client
client.close()

More advanced usage and related docs can be found here: https://github.com/abhiTronix/vidgear/wiki/NetGear

Solution 5:^[5]

as @Rohan Sawant said i used zmq library without using base64 encoding. here is the new code

Streamer.py

import base64
import cv2
import zmq
import numpy as np
import time

context = zmq.Context()
footage_socket = context.socket(zmq.PUB)
footage_socket.connect('tcp://192.168.1.3:5555')

camera = cv2.VideoCapture(0)  # init the camera

while True:
        try:
                grabbed, frame = camera.read()  # grab the current frame
                frame = cv2.resize(frame, (640, 480))  # resize the frame
                encoded, buffer = cv2.imencode('.jpg', frame)
                footage_socket.send(buffer)


        except KeyboardInterrupt:
                camera.release()
                cv2.destroyAllWindows()
                break

Viewer.py

import cv2
import zmq
import base64
import numpy as np

context = zmq.Context()
footage_socket = context.socket(zmq.SUB)
footage_socket.bind('tcp://*:5555')
footage_socket.setsockopt_string(zmq.SUBSCRIBE, np.unicode(''))

while True:
    try:
        frame = footage_socket.recv()
        npimg = np.frombuffer(frame, dtype=np.uint8)
        #npimg = npimg.reshape(480,640,3)
        source = cv2.imdecode(npimg, 1)
        cv2.imshow("Stream", source)
        cv2.waitKey(1)

    except KeyboardInterrupt:
        cv2.destroyAllWindows()
        break

Solution 6:^[6]

Recently I publish imagiz package for Fast and none blocking live video streaming over network with OpenCV and ZMQ.

https://pypi.org/project/imagiz/

Client :

import imagiz
import cv2


client=imagiz.Client("cc1",server_ip="localhost")
vid=cv2.VideoCapture(0)
encode_param = [int(cv2.IMWRITE_JPEG_QUALITY), 90]

while True:
    r,frame=vid.read()
    if r:
        r, image = cv2.imencode('.jpg', frame, encode_param)
        client.send(image)
    else:
        break

Server :

import imagiz
import cv2

server=imagiz.Server()
while True:
    message=server.recive()
    frame=cv2.imdecode(message.image,1)
    cv2.imshow("",frame)
    cv2.waitKey(1)

Solution 7:^[7]

I have made it to work on my MacOS.

I used the code from @mguijarr and changed the struct.pack from "H" to "L".

# Server.py:
import socket
import sys
import cv2
import pickle
import numpy as np
import struct ## new


HOST=''
PORT=8089
    
s=socket.socket(socket.AF_INET,socket.SOCK_STREAM)
print 'Socket created'
    
s.bind((HOST,PORT))
print 'Socket bind complete'
s.listen(10)
print 'Socket now listening'
    
conn,addr=s.accept()
    
# new
data = ""
payload_size = struct.calcsize("L") 
while True:
    while len(data) < payload_size:
        data += conn.recv(4096)
    packed_msg_size = data[:payload_size]
    data = data[payload_size:]
    msg_size = struct.unpack("L", packed_msg_size)[0]
    while len(data) < msg_size:
        data += conn.recv(4096)
    frame_data = data[:msg_size]
    data = data[msg_size:]
    
    
    frame=pickle.loads(frame_data)
    print frame
    cv2.imshow('frame',frame)
        
    key = cv2.waitKey(10)
    if (key == 27) or (key == 113):
        break
    
cv2.destroyAllWindows()

# Client.py
import cv2
import numpy as np
import socket
import sys
import pickle
import struct ### new code


cap=cv2.VideoCapture(0)
clientsocket=socket.socket(socket.AF_INET,socket.SOCK_STREAM)
clientsocket.connect(('localhost',8089))

while True:
    ret,frame=cap.read()
    data = pickle.dumps(frame) ### new code
    clientsocket.sendall(struct.pack("L", len(data))+data) ### new code

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution	Source
Solution 1	Ryu S.
Solution 2	Rohan Sawant
Solution 3	Ben
Solution 4
Solution 5	Anagnostou John
Solution 6	Phonix
Solution 7	Bar?? ?enyerli

'Sending live video frame over network in python opencv

Solution 1:[1]

Solution 2:[2]

Solution 3:[3]

Solution 4:[4]