'Selenium(Python) wait 10 sec for searching id on the page
I have some example of the code:
def wait_for_id(self, id):
self.wait.until(EC.element_to_be_clickable((By.ID, id)))
return self.browser.find_element_by_id(id)
I need to wait only 10 sec for finding this element on the page. If it will be more than 10 sec, so need to fail and continue next row.
self.wait_for_id('quit').click()
So by default, there is a time for waiting is 30 minutes(around this time)... then it failed as I expected, but I want to put for example only 2 minutes maximum on waiting for failure.
Solution 1:[1]
The WebDriverWait() constructor takes a WebDriver instance and timeout in seconds.
So essentially before the following code block:
def wait_for_id(self, id):
self.wait.until(EC.element_to_be_clickable((By.ID, id)))
return self.browser.find_element_by_id(id)
somewhere in your code you have defined wait as:
self.wait = WebDriverWait(self.driver, 1800)
Hence, time for waiting is 30 minutes.
To reduce the waiting time to 2 minutes you need to change it as:
self.wait = WebDriverWait(self.driver, 120)
Sources
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Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | undetected Selenium |
