'remove characters before and after character in java

I need to delete all characters before and after a specific character using java programming for example:

input: ab*cd output:ad

input: ab**cd output:ad

import java.util.Scanner;

public class Starstring {
    public static void main(String[] args) {
        String str1;
        String res="";
        int n,i=0;

        Scanner sc=new Scanner(System.in);
        System.out.println("Enter the string");
        str1=sc.next();
        res=str1;
        StringBuffer a = new StringBuffer(str1);
        n=str1.length()-1;
        for(i=0;i<n;i++)
        {
            if(str1.charAt(i)=='*')
            {
                res=a.delete(i-1, i+2).toString();
            }
        }
        System.out.println("The final string is"+res);
    }

}

I am getting expected output for case 1 but case 2 wrong output with ac as output.I don't know where I am going wrong.Someone please help me.Thanks in advance:)

javastring


Solution 1:[1]

You can use regex to replace character group in your string. To remove * and 1 character before & after it:

Pattern pt = Pattern.compile(".\\*+."); 
Matcher match = pt.matcher(input);
String output = match.replaceAll("");
//System.out.println(output);

Solution 2:[2]

You can do it like this : 

    String str1;
    int n;

    Scanner sc=new Scanner(System.in);
    System.out.println("Enter the string");
    str1=sc.next();

    sc.close();

    StringBuffer a = new StringBuffer(str1);
    n=a.length();
    for(int i=0;i<n;i++)
    {
        if(str1.charAt(i)=='*')
        {
            int aa = i-1;
            int bb = i+1;
            for(;bb<n; bb++){
                if(str1.charAt(bb)!='*'){
                    break;
                }
            }
            a.delete( aa, bb+1 );
            i = bb;

        }
    }
    String res = a.toString();
    System.out.println("The final string is"+res);

But a better java regex way is :

After reading value from scanner -

    String res2 = str1.replaceAll( ".[\\*]+.", "" );
    System.out.println("The final string is"+res2);

Solution 3:[3]

Using @Vasan regex.. below is the code.

public static void main(String[] args) {
        String str1;
        String res="";
        int n;

        Scanner sc=new Scanner(System.in);
        System.out.println("Enter the string");
        str1=sc.next();
        res=str1;
        StringBuffer a = new StringBuffer(str1);
        n=str1.length()-1;

        String[] splitVal = str1.split(".\\*+.");
        String newString ="";
        for(int i=0; i<splitVal.length; i++){
            newString = newString + splitVal[i];
        }

        System.out.println("The final string is "+newString);
    }

Hope you understand.

Solution 4:[4]

Try this:

public static void main(String[] args) {
    System.out.println("Enter the string");
    Scanner sc = new Scanner(System.in);
    String str1 = sc.nextLine();
    String[] separated = str1.split(".\\*+.");
    String result = "";
    for(String str : separated) {
        result += str;
    }
    System.out.println(result);
}

Solution 5:[5]

what if input is : *abc* or ab*c*de

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 Nam Tran
Solution 2 Mahendra
Solution 3 Sh4m
Solution 4 Vijaya Pandey
Solution 5 Suri

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