'React-native Linking.openUrl doesn't open link to another screen
I have a react-native app and I'm trying to "redirect" user to another screen(based on url received from a deep linking", for example, if an user is on Screen A, then exits the app, clicks on the link, Screen A opens up and from Screen A the user should be redirected to the screen B. I'm getting the deep link on the screen A but can't redirect user to Screen B on android. My code:
Linking.openURL(deepLink)
The deeplink has this structure:
myApp://mainPage/address
When I use Linking.canOpenURL => it throws an error. I can't seem to figure out what I'm doing wrong, any suggestion is appreciated.thank you
Solution 1:[1]
Solved: posting here in case anyone else runs into the same issue - I changed Linking.openURL(deepLink) to branch.openURL(deepLink) and it worked
Sources
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Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | new_reactjs |