Python - Get Yesterday's date as a string in YYYY-MM-DD format

Question

As an input to an API request I need to get yesterday's date as a string in the format YYYY-MM-DD. I have a working version which is:

yesterday = datetime.date.fromordinal(datetime.date.today().toordinal()-1)
report_date = str(yesterday.year) + \
   ('-' if len(str(yesterday.month)) == 2 else '-0') + str(yesterday.month) + \
   ('-' if len(str(yesterday.day)) == 2 else '-0') + str(yesterday.day)

There must be a more elegant way to do this, interested for educational purposes as much as anything else!

Answer 1

An alternative answer that uses today() method to calculate current date and then subtracts one using timedelta(). Rest of the steps remain the same.

https://docs.python.org/3.7/library/datetime.html#timedelta-objects

from datetime import date, timedelta
today = date.today()
yesterday = today - timedelta(days = 1)
print(today)
print(yesterday)

Output: 
2019-06-14
2019-06-13

Answer 2

>>> import datetime
>>> datetime.date.fromordinal(datetime.date.today().toordinal()-1).strftime("%F")
'2015-05-26'

Answer 3

Calling .isoformat() on a date object will give you YYYY-MM-DD

from datetime import date, timedelta
(date.today() - timedelta(1)).isoformat()

Answer 4

I'm trying to use only import datetime based on this answer.

import datetime

oneday = datetime.timedelta(days=1)
yesterday = datetime.date.today() - oneday