'Print date from input ID user in java
I have to make a code that take an user name input and then an ID number that is based format as ( 1102199344556699 - where the first 8 characters is his day of birth). My code:
import java.time.format.DateTimeFormatter;
import java.time.temporal.TemporalAccessor;
import java.util.Locale;
import java.util.Scanner;
public class Main {
public static void main(String[] args) throws Exception {
//user input
Scanner scanner = new Scanner(System.in);
System.out.println("Enter your name: ");
int length = scanner.nextLine()
.length();
System.out.println(length);
//user id input
Scanner scanner2 = new Scanner(System.in);
System.out.println("Enter your id number");
String idNUmber = scanner2.nextLine();
if (idNUmber.length() < 11) {
throw new InvlaidIdException("invalid");
} else {
String dateOfBirth = idNUmber.substring(0, 8);
//found this way,on the output is giving me from input -110219935656525
//output is ok but as you can see on My output i get some extra things (please see OUTPUT)
TemporalAccessor date = DateTimeFormatter.ofPattern("ddMMyyyy").withLocale(Locale.FRANCE).parse(dateOfBirth);
System.out.println(date);
}
}
}
INPUT user Id -110219935656525
OUTPUT:
This is the birthday date: {},ISO resolved to 1993-02-11
How can i get rid of {},ISO resolved to ? Thanks,
Sources
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