'Multiline log records in syslog
So I've configured my Python application to log to syslog with Python's SysLogHandler, and everything works fine. Except for multi-line handling. Not that I need to emit multiline log records so badly (I do a little), but I need to be able to read Python's exceptions. I'm using Ubuntu with rsyslog 4.2.0. This is what I'm getting:
Mar 28 20:11:59 telemachos root: ERROR 'EXCEPTION'#012Traceback (most recent call last):#012 File "./test.py", line 22, in <module>#012 foo()#012 File "./test.py", line 13, in foo#012 bar()#012 File "./test.py", line 16, in bar#012 bla()#012 File "./test.py", line 19, in bla#012 raise Exception("EXCEPTION!")#012Exception: EXCEPTION!
Test code in case you need it:
import logging
from logging.handlers import SysLogHandler
logger = logging.getLogger()
logger.setLevel(logging.INFO)
syslog = SysLogHandler(address='/dev/log', facility='local0')
formatter = logging.Formatter('%(name)s: %(levelname)s %(message)r')
syslog.setFormatter(formatter)
logger.addHandler(syslog)
def foo():
bar()
def bar():
bla()
def bla():
raise Exception("EXCEPTION!")
try:
foo()
except:
logger.exception("EXCEPTION")
Solution 1:[1]
Alternatively, if you want to keep your syslog intact on one line for parsing, you can just replace the characters when viewing the log.
tail -f /var/log/syslog | sed 's/#012/\n\t/g'
Solution 2:[2]
Another option would be to subclass the SysLogHandler and override emit() - you could then call the superclass emit() for each line in the text you're sent. Something like:
from logging import LogRecord
from logging.handlers import SysLogHandler
class MultilineSysLogHandler(SysLogHandler):
def emit(self, record):
if '\n' in record.msg:
record_args = [record.args] if isinstance(record.args, dict) else record.args
for single_line in record.msg.split('\n'):
single_line_record = LogRecord(
name=record.name,
level=record.levelno,
pathname=record.pathname,
msg=single_line,
args=record_args,
exc_info=record.exc_info,
func=record.funcName
)
super(MultilineSysLogHandler, self).emit(single_line_record)
else:
super(MultilineSysLogHandler, self).emit(record)
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Nick Zalutskiy |
| Solution 2 | Hamish Downer |
