More elegant way to create a python dictionary from a map object and list

Question

someList=['this','that','the_other','and_this']
timeFrame='hour'
getDatafromFile(some_string,time_frame):
    do some processing
    return dataframeObject

The end result is a dictionary with a keyed on the strings from someList and a value of the object returned from getDatafromFile. The following code I wrote accomplishes this but it seems there should be an easier way with less lines of code.

with ThreadPoolExecutor() as executor:
    results=executor.map(getDatafromFile, [*someList],[timeFrame for i in range(len(someList))])

from this point forward is there a more elegant way to do this with less lines of code? Some sort of comprehension, perhaps. I thought about returning the string value and dataframe object back from the function, but it seems asinine to return back a parameter.

 pdDataList=[]
 for result in results:        
     pdDataList.append(result)
 df_dict=dict(zip(someList,pdDataList))

Answer 1

You can use dict comprehension syntax:

{key: getDatafromFile(key, timeFrame) for key in someList}

Answer 2

From the answer below, which can't work because the function has to be called by the threadpool executor, I got the idea of how to do the four lines of code in one line. Apparently a map object can be iterated as if it's a list. I'm sure there's a dictionary comprehension equivalent but this is just as simple of a one liner:

df_dict=dict(zip(someList,results))

Thus the entire code is:

with ThreadPoolExecutor() as executor:
    results=executor.map(getDatafromFile, [*someList],[timeFrame for i in range(len(someList))])
df_dict=dict(zip(someList,results))