My goal is to compare two lists as follows: Take every item in long_list and compare it for substrings to the entire short_list. If there is a match, add the it
I have 4 objects. class MyObject: def __init__(self, id: int, result_name: str): self.id = id self.result = Result(result_name) class Resu
I have a 2D-List contains unequal size lengths, like this: lst = [[1,2,3],[-1,2,4],[0,2],[2,-3,6]] I use this code to insert a 0 if element size less 3: newlis
This list comprehension does not work: buy_prices = [(buylow := round(0.997 + ii/10000.0, 5), max(jj, buylow)) for jj in [buylow, 0.9982] for ii in range(21)]
This list comprehension works, but I’d rather have it written like conventional loops: Here is the list comprehension: with open(sys.argv[1], 'r') as f:
I am looking to compare two instances of the same class, but only the items for which both are not None. for instance, I will have a Bolt class, and one instanc
I have this array of strings of comma-separated numbers: data = ['1,14.23,1.71,2.43,15.6,127,2.8,3.06,.28,2.29,5.64,1.04,3.92,1065', '
I am trying to extract all the texts in span into list, using the following HTML code from Selenium webdriver method: ['1a', '1b', '1c', '2a', ' ', ' ', '3a', '
We know that list comprehensions and do expressions are equivalent for lists. Also list comprehensions are redundant. But can someone explain how exactly do not
How can I use scipy.interpolate.interp1d when my x array is an N-D array, instead of a 1-D array, without using a loop? The function f from interp1d then needs
!!! I know I could use Counter() here, but that's not the point !!! Giving the code below: test =[['a',1],['a',2],['b',3], ['c',5],['a',7],['c',9]] {i:[test[x]
Let's say I have a dict in Python that follows this structure: dict_a = {"a": [1,2,3]} I want to produce an output to 'decouple' dict_a in a list of 3 separate
I'm trying to "paste" the values contained in the 1D array dataslice (1x8) into the 2D array values_matrix (9x9), following the position indices contained in th
Let's say I have a list[str] object containing timestamps in "HH:mm" format, e.g. timestamps = ["22:58", "03:11", "12:21"] I want to convert it to a list[int]
I would like to know if there is a better way to print all objects in a Python list than this : myList = [Person("Foo"), Person("Bar")] print("\n".join(map(str
Ok. I'm looking for the smartest and more compact way to do this function def f(): [[a,b,c] for a in range(6) for b in range(6) for c in range(6)] which
Consider a list I want to parse using a for : friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"] for i in friends: print i will retur
I have a list that looks like [(1,2,5),(2,10,13),(5,24,56),(1,8,10),(2,3,11)] How can I produce a dictionary by grouping by first element of tuples and find
I want to find a list comprehension in python source code, for that I tried to use Pygments, but it didn't find the way to do that. To be more specific, I wan
Using Pandas I have a df that is 14000 rows by 56 columns (keywords) I have a keyword list (full_keys) that is 1406 items and an empty (0) dataframe (called key