'Merge specifications of different types in Criteria Query Specifications
I'm having an Activity entity which is in @ManyToOne relationship with Event entity and their corresponding metamodels - Activity_ and Event_ were generated by JPA model generator.
I've created specialized classes ActivitySpecifications and EventSpecifications. Those classes contain only static methods whose return Specification. For example:
public interface EventSpecifications {
static Specification<Event> newerThan(LocalDateTime date) {
return (root, cq, cb) -> cb.gt(Event_.date, date);
}
...
}
so when I want to build query matching multiple specifications, I can execute following statement using findAll on JpaSpecificationExecutor<Event> repository.
EventSpecifications.newerThan(date).and(EventSpecifications.somethingElse())
and ActivitySpecifications example:
static Specification<Activity> forActivityStatus(int status) { ... }
How do I use EventSpecifications from ActivitySpecifications ? I mean like merge specifications of different type. I'm sorry, but I don't even know how to ask it properly, but theres simple example:
I want to select all activities with status = :status and where activity.event.date is greater than :date
static Specification<Activity> forStatusAndNewerThan(int status, LocalDateTime date) {
return forActivityStatus(status)
.and((root, cq, cb) -> root.get(Activity_.event) ....
// use EventSpecifications.newerThan(date) somehow up there
}
Is something like this possible?
The closest thing that comes to my mind is using the following:
return forActivityStatus(status)
.and((root, cq, cb) -> cb.isTrue(EventSpecifications.newerThan(date).toPredicate(???, cq, cb));
where ??? requires Root<Event>, but I can only get Path<Event> using root.get(Activity_.event).
Solution 1:[1]
Consider the following :
ClassA {
id;
}
ClassB {
foreignId; //id of A
}
For combining Specification<ClassA> specA, Specification<ClassB> specB
specB = specB.and(combineSpecs(specA);
private static Specification<ClassB> combineSpecs(Specification<ClassA> specA) {
return (root_b,query,builder) {
Subquery<ClassA> sub = query.subquery(ClassA.class);
Root<ClassA> root_a = sub.from(ClassA.class);
Predicate p1 = specA.toPredicate(root_a,query,builder);
Predicate p2 = builder.equal(root_a.get("id"),root_b.get("foreignId"));
Predicate predicate = builder.and(p1,p2);
sub.select(root_a).where(predicate);
return builder.exists(sub);
};
}
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Leena |
