Making if statement if the character in the index is equal to [closed]

Question

How to make an if statement only giving the index of character in the string and if its equall to example

# i know this is wrong so plss help me
k = "klk"
if k[2] == "l":
    print("done")

If i print its only program finish

Answer 1

Python indexes start at 0.

k[0] is k

k[1] is l

k[2] is k

You would need to do

k = "klk"
if k[1] == "l":
    print("done")

You can also go in a reverse form with negative numbers:

test = "hello"
if test[-2] == "l":
    print("done")

test[-1] is o

test[-2] is l

test[-3] is l

test[-4] is e

Answer 2

k = input("enter example: ")
if k[1] == "l" and len(k) >= 2:
    print("k contains l")

I would highly recommend Tech With Tim's video "Python as fast as possible": https://www.youtube.com/watch?v=VchuKL44s6E