'I want to count subscription days
I want to count subscription days i tried using timedelta() but I need to skip Thursday while calculating, its a 26 day subscription but no delivery on Thursday
started = datetime.date(2022 , 5 , 22 )
subscription = datetime.timedelta(26)
print( started+subscription )
Solution 1:[1]
To count (increment daily) or to calculate ? Calculation is a calendar problem - you need to calculate the number of exclusion days (Thursdays's).
Your case is easy since there is always exactly 4 Thursdays in any 26-day calendar span.
Solution 2:[2]
Both datetime.date and datetime.datetime objects have a today method that return respectively a Date and a Datetime object.
Which both have a weekday and isoweekday methods. weekday count from Monday = 0, while isoweekday count from Monday = 1:
from datetime import date, datetime
if date.today().weekday() == 0:
# it is Monday
if datetime.today().isoweekday() == 1:
# it is Monday
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | ZXX |
| Solution 2 | Kshitiz305 |
