How to tell if a date is between two other dates?

Question

I have the following codes:

if date in (start, end):
        print('in between')
else:
        print('No!')

date, start and end are all variables with the format of 1/1. What should I do to have it print out the right result? i tried date as 10/2, start as 3/14 and end as 11/7 and it's print 'No!', which means it's not running right. I guess have to format them to a date format and then compare them.

Answer 1

If you convert all your dates to datetime.date, you can write the following:

if start <= date <= end:
    print("in between")
else:
    print("No!")

Answer 2

Use datetime.date:

http://docs.python.org/library/datetime.html#datetime.date

< operator is overloaded specially for you.

date1 < date2 - date1 is considered less than date2 when date1 precedes date2 in time.

>>> from datetime import date
>>> d1 = date(2011, 3, 28)
>>> d2 = date(2011, 3, 22)
>>> d3 = date(2011, 4, 3)
>>> d2 < d1 < d3
True

Or in your prgram:

from datetime import date

d1 = date(2011, 3, 28)
d2 = date(2011, 3, 22)
d3 = date(2011, 4, 3)

if d2 < d1 < d3:
    print('in between')
else:
    print('No!')

Answer 3

from datetime import datetime

date_format = "%m/%d/%Y"

a = datetime.strptime('8/18/2008', date_format)

b = datetime.strptime('9/26/2007', date_format) # Date to be checked

c = datetime.strptime('9/25/2008', date_format)

d = datetime.strptime('8/18/2008', date_format)  #Date entered here should always be the same as 'a'

delta1 = b - a

delta2 = c - b

delta3 = d - a

if delta1.days >= delta3.days and delta2.days >= delta3.days:

    print('In between')

else:

    print('Not in between')