'How to make a loop that validates the user-input dates based on the functions created?
I am not using any datetime module. I created my own functions to calculate the day, month, and year. I want to calculate the refunds based on the date. If the date is invalid, it should ask the user to try again until a date is true.
year = 0
month = 0
day = 0
money_owed = 0
def if_leap_year(year):
if (year % 400 == 0): return 366
elif (year % 100 == 0): return 365
elif (year % 4 == 0): return 366
else:
return 365
#print(if_leap_year(year))
def days_in_month(month, year):
if month in {1, 3, 5, 7, 8, 10, 12}:
return 31
if month == 2:
if if_leap_year(year):
return 29
return 28
return 30
#print(days_in_month(month, year))
def is_valid_date(year, month, day):
if days_in_month(month, year)<day:#checks if the given day is possible
given the month
return False
else:
return True
def days_left_in_year(month, day, year):
daysInMonth = [31,28,31,30,31,30,31,31,30,31,30,31]
daysLeft = (if_leap_year(year) if month < 3 else 365) -
sum(daysInMonth[:month - 1]) - day
return daysLeft
def refund_period():
month = int(input("Enter the month of the year: "))
day = int(input("Enter the day of the year: "))
year = int(input("Enter the year to determine the number of days: "))
if is_valid_date(year , month , day):
money_owed = (days_left_in_year(month, day, year) /
if_leap_year(year)) * 278
return round(money_owed, 2)
else:
print("Your date is invalid, try again.")
while is_valid_date(year, month, day):
print('you will be refunded','$', + refund_period())
break
else:
print("Your date is invalid, try again.")
I am getting:
you will be refunded $ -8.38
even though the calculation shouldn't be performed since the date is invalid
Solution 1:[1]
You are setting year =0 , month =0, day = 0 in first loop.
Also the while is not clear. All your functions return an int so never validate if the date is correct.
Maybe you can create a function to validate the date something like this :
def is_valid_date(year , month , day):
if month <1 or month >12: #Validate a allowed month
return False
if day <1 or day > days_in_month(month, year): # validate an allowed day for the month
return False
return True
and you can change this function :
def refund_period():
month = int(input("Enter the month of the year: "))
day = int(input("Enter the day of the year: "))
year = int(input("Enter the year to determine the number of days: "))
if is_valid_date(year , month , day):
money_owed = (days_left_in_year(month, day, year) / if_leap_year(year)) * 278
return round(money_owed, 2)
else :
print("Your date is invalid, try again.")
Just a couple of comments:
You are getting the year, month, and day using
input()so you don't need to create global variables for that.you don't need to ask if
if_leap_year(year) == 365 or 366because this function returns 365 or 366 so you can use it directly when you calculate the money_owned, as I do.Also you can use
if_leap_year(year)instead(if_leap_year(year) if month < 3 else 365). That functions return 366 or 365, you dont need to validate again.And you can use list comprehension for you
daysInMonthvariable insidedays_left_in_yearfunction :daysInMonth = [days_in_month(m, year) for m in range(1,13)]
Solution 2:[2]
Your while loop is not comparing the function value but just checking if the object exists. Instead of conditions like while days_left_in_year(month, day, year), use conditions like while days_left_in_year(month, day, year)<30 (assuming you wanted to deny refunds on orders older than 30 days.
To validate dates, add the following function under your comment #print(days_in_month(month, year)):
def is_valid_date(year, month, day)
if days_in_month(month, year)<day:#checks if the given day is possible given the month
return False
else:
return True
then your condition should look something like this:
if ((is_valid_date(year, month, day) == True) and (month<13)):
print('you will be refunded','$', + refund_period())
else:
print("Your date is invalid, try again.")
Sources
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Source: Stack Overflow
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