How to let Python execute script in each folder [closed]

Question

I struggled with this question for 2 days and has no idea. I have 3 folders containing 3 individual python scripts each folder script run a function.

My question is how can I access them individually?

for only 1 folder, I create, say app.py with all routes inside. but how can I access 3 folder individually and can run individual function?

My file skeleton likes:

app.py (entrance)
|---departmentA
......|-------runme.py
......|-------templates
...........|-----index.html
|---departmentB
......|-------runme.py
......|-------templates
...........|-----index.html
|---departmentC
......|-------runme.py
......|-------templates
...........|-----index.html

Thanks Alex

Answer 1

File Structure:

app.py
/departmentA
    __init__.py
    routes.py
    runme.py
    /pages/departmentA
        index.html

app.py

from flask import Flask
import departmentA

skill_app = Flask(__name__)
skill_app.register_blueprint(departmentA.bp)

print(departmentA.my_func())

skill_app.run()

/departmentA/init.py

from .routes import bp
from .runme import my_func

/departmentA/routes.py

from flask import Blueprint, render_template
from .runme import my_func

bp = Blueprint('dept_A', __name__, template_folder='pages', url_prefix='/department_A')

@bp.route('/')
def index():
    print(my_func())
    return render_template('departmentA/index.html')

/departmentA/runme.py

def my_func():
    return "Hello World!"

Use same format in other departments.