'How to determine an object's value in Python
From the Documentation
Every object has an identity, a type and a value.
- type(obj)returns the type of the object
- id(obj)returns the id of the object
is there something that returns its value? What does the value of an object such as a user defined object represent?
Solution 1:[1]
Note that not all objects have a __dict__ attribute, and moreover, sometimes calling dict(a) where the object a can actually be interpreted as a dictionary will result in a sensible conversion of a to a native python dictionary.  For example, with numpy arrays:
In [41]: a = np.array([[1, 2], [3, 4]])
In [42]: dict(a)
Out[42]: {1: 2, 3: 4}
But a does not have an attribute 1 whose value is 2.  Instead, you can use hasattr and getattr to dynamically check for an object's attributes:
In [43]: hasattr(a, '__dict__')
Out[43]: False
In [44]: hasattr(a, 'sum')
Out[44]: True
In [45]: getattr(a, 'sum')
Out[45]: <function ndarray.sum>
So, a does not have __dict__ as an attribute, but it does have sum as an attribute, and a.sum is getattr(a, 'sum').
If you want to see all the attributes that a has, you can use dir:
In [47]: dir(a)[:5]
Out[47]: ['T', '__abs__', '__add__', '__and__', '__array__']
(I only showed the first 5 attributes since numpy arrays have lots.)
Solution 2:[2]
For every Python class, there are special functions executed for different cases. __str__ of a class returns the value that will be used when called as print(obj) or str(obj).
Example:
class A:
    def __init__(self):
        self.a = 5
    def __str__(self):
        return "A: {0}".format(self.a)
obj = A()
print(obj)
# Will print "A: 5"
Solution 3:[3]
to really see your object values/attributes you should use the magic method __dict__.
Here is a simple example:
class My:
    def __init__(self, x):
        self.x = x
        self.pow2_x = x ** 2
a = My(10)
# print is not helpful as you can see 
print(a) 
# output: <__main__.My object at 0x7fa5c842db00>
print(a.__dict__.values())
# output: dict_values([10, 100])
or you can use:
print(a.__dict__.items())
# output: dict_items([('x', 10), ('pow2_x', 100)])
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source | 
|---|---|
| Solution 1 | Andrew | 
| Solution 2 | |
| Solution 3 | 
