'How to convert multicharacter single line into string in Python
Hello I have line like below in a file
I want to convert Text :0 to 8978 as a single string. And same for other part i.e Text:1 to 8978.
Text:0
6786993cc89 70hgsksgoop 869368
7897909086h fhsi799hjdkdh 099h
Gsjdh768hhsj dg9978hhjh98 8978
Text:1
8786993cc89 70hgsksgoop 869368
7897909086h fhsi799hjdkdh 099h
Gsjdh768hhsj dg9978hhjh98 8978
I am getting output as
6
7
G
8
7
G
But i want output as from string one and from string two as
6 8
Code is :
file = open ('tem.txt','r') lines = file.readlines() print(lines) for line in lines: line=line.strip() linex=line.replace(' ','') print(linex) print (linex[0])
Solution 1:[1]
I'm not sure about what exact do you need, so:
#1. If need only print the first number (6), I think your code is right.
#2. If you need to print the first part of string(before "space"), it can help you:
line="6786993cc8970hgsksgoop869368 7897909086hfhsi799hjdkdh099h Gsjdh768hhsjdg9978hhjh988978"
print(line[0])
print(line.split(' ')[0])
EDIT
To read a file....
file = open('file.txt', 'r')
Lines = file.readlines()
file.close()
for line in Lines:
print(line.split(' ')[0])
New EDIT
First you need to format your file to after that get the first element. Try this please:
file = open ('tem.txt','r')
lines = file.readlines()
file.close()
linesArray = []
lineTemp = ""
for line in lines:
if 'Text' in line:
if lineTemp:
linesArray.append(lineTemp)
lineTemp = ""
else:
lineTemp += line.strip()
linesArray.append(lineTemp)
for newline in linesArray:
print(newline.split(' ')[0][0])
Solution 2:[2]
This should work only if you want to view the first character. Essentially, this code will read your text file, convert multiple lines in the text file to one single string and print out the required first character.
with open(r'tem.txt', 'r') as f:
data = f.readlines()
line = ''.join(data)
print(line[0])
EDITED RESPONSE
Try using regex. Hope this helps.
import re
pattern = re.compile(r'(Text:[0-9]+\s)+')
with open(r'tem.txt', 'r') as f:
data = f.readlines()
data = [i for i in data if len(i.strip())>0]
line = ' '.join([i.strip() for i in data if len(i)>0]).strip()
occurences = re.findall(pattern, line)
for i in occurences:
match_i = re.search(i, line)
start = match_i.end()
print(line[start])
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
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| Solution 1 | |
| Solution 2 |
