How do I make an optional parameter in a slash command (Pycord)

Question

I have a slash command in my Pycord bot. Here is the code:

@bot.slash_command(name='greet', description='Greet someone!')
async def greet(ctx, name):
    await ctx.send('Hello ' + name + '!')

How would I make "name" an optional parameter? I tried setting name=None, but it doesn't work.

Answer 1

you could find examples from pycord repo examples/app_commands

# example.py

import discord
import json
from discord.ext import commands
from discord.commands.context import ApplicationContext
from discord.commands import Option
from discord.file import File
import os

# example for getting image
def get_image_paths():
    file_paths = []

    for fn in os.listdir('./img'):
        file_paths.append(os.path.join(os.getcwd(), 'img', fn))

    return file_paths

async def images(ctx : ApplicationContext):
    imgs = get_image_paths()

    files = [File(path) for path in imgs]

    await ctx.respond(files=files)

async def say_hello(ctx  : ApplicationContext):
    await ctx.respond(f"hello")

# guild_ids are optional, but for fast registration I recommand it
# name (optional) : if not provided, your command name will shown as function name; this case "my_command"
@commands.slash_command(
    name = "my_command",
    description= "This is sample command",
    guild_ids = [ <your guild(server) id> ],
)
async def sample_command(
    ctx : ApplicationContext,
    opt: Option(str,
                    "reaction you want", 
                    choices=["Hi", "image"], 
                    required=True)
):

    if opt == "Hi":
        await say_hello(ctx)

    if opt == "image":
        await images(ctx)

it will look like :

import this script as from example import library_command

and don't forget to add commands

# at main.py
...

bot.add_application_command(library_command)
...

bot.run(<your token>)

you must send as 'respond' not 'send' or discord will count as "failed to reply"