'How do I initialize a byte array in Java?

I have to store some constant values (UUIDs) in byte array form in java, and I'm wondering what the best way to initialize those static arrays would be. This is how I'm currently doing it, but I feel like there must be a better way.

private static final byte[] CDRIVES = new byte[] { (byte)0xe0, 0x4f, (byte)0xd0,
    0x20, (byte)0xea, 0x3a, 0x69, 0x10, (byte)0xa2, (byte)0xd8, 0x08, 0x00, 0x2b,
    0x30, 0x30, (byte)0x9d };
private static final byte[] CMYDOCS = new byte[] { (byte)0xba, (byte)0x8a, 0x0d,
    0x45, 0x25, (byte)0xad, (byte)0xd0, 0x11, (byte)0x98, (byte)0xa8, 0x08, 0x00,
    0x36, 0x1b, 0x11, 0x03 };
private static final byte[] IEFRAME = new byte[] { (byte)0x80, 0x53, 0x1c,
    (byte)0x87, (byte)0xa0, 0x42, 0x69, 0x10, (byte)0xa2, (byte)0xea, 0x08,
    0x00, 0x2b, 0x30, 0x30, (byte)0x9d };
...
and so on

Is there anything I could use that may be less efficient, but would look cleaner? for example:

private static final byte[] CDRIVES =
    new byte[] { "0xe04fd020ea3a6910a2d808002b30309d" };

java arrays byte

Solution 1:^[1]

You can use an utility function to convert from the familiar hexa string to a byte[]. When used to define a final static constant, the performance cost is irrelevant.

Since Java 17

There's now java.util.HexFormat which lets you do

byte[] CDRIVES = HexFormat.of().parseHex("e04fd020ea3a6910a2d808002b30309d");

This utility class lets you specify a format which is handy if you find other formats easier to read or when you're copy-pasting from a reference source:

byte[] CDRIVES = HexFormat.ofDelimiter(":")
    .parseHex("e0:4f:d0:20:ea:3a:69:10:a2:d8:08:00:2b:30:30:9d");

Before Java 17

I'd suggest you use the function defined by Dave L in Convert a string representation of a hex dump to a byte array using Java?

byte[] CDRIVES = hexStringToByteArray("e04fd020ea3a6910a2d808002b30309d");

I insert it here for maximum readability :

public static byte[] hexStringToByteArray(String s) {
    int len = s.length();
    byte[] data = new byte[len / 2];
    for (int i = 0; i < len; i += 2) {
        data[i / 2] = (byte) ((Character.digit(s.charAt(i), 16) << 4)
                             + Character.digit(s.charAt(i+1), 16));
    }
    return data;
}

Solution 2:^[2]

byte[] myvar = "Any String you want".getBytes();

String literals can be escaped to provide any character:

byte[] CDRIVES = "\u00e0\u004f\u00d0\u0020\u00ea\u003a\u0069\u0010\u00a2\u00d8\u0008\u0000\u002b\u0030\u0030\u009d".getBytes();

Solution 3:^[3]

In Java 6, there is a method doing exactly what you want:

private static final byte[] CDRIVES = javax.xml.bind.DatatypeConverter.parseHexBinary("e04fd020ea3a6910a2d808002b30309d")

Alternatively you could use Google Guava:

import com.google.common.io.BaseEncoding;
private static final byte[] CDRIVES = BaseEncoding.base16().lowerCase().decode("E04FD020ea3a6910a2d808002b30309d".toLowerCase());

The Guava method is overkill, when you are using small arrays. But Guava has also versions that can parse input streams. This is a nice feature when dealing with big hexadecimal inputs.

Solution 4:^[4]

You can use the Java UUID class to store these values, instead of byte arrays:

UUID

public UUID(long mostSigBits,
            long leastSigBits)

Constructs a new UUID using the specified data. mostSigBits is used for the most significant 64 bits of the UUID and leastSigBits becomes the least significant 64 bits of the UUID.

Solution 5:^[5]

Smallest internal type, which at compile time can be assigned by unsigned hex numbers is char, as

private static final char[] CDRIVES_char = new char[] {0xe0, 0xf4, ...};

In order to have an equivalent byte array one might deploy conversions as

public static byte[] charToByteArray(char[] x)
{
    final byte[] res = new byte[x.length];
    for (int i = 0; i < x.length; i++)
    {
        res[i] = (byte) x[i];
    }
    return res;
}

public static byte[][] charToByteArray(char[][] x)
{
    final byte[][] res = new byte[x.length][];
    for (int i = 0; i < x.length; i++)
    {
        res[i] = charToByteArray(x[i]);
    }
    return res;
}

Solution 6:^[6]

A solution with no libraries, dynamic length returned, unsigned integer interpretation (not two's complement)

    public static byte[] numToBytes(int num){
    if(num == 0){
        return new byte[]{};
    }else if(num < 256){
        return new byte[]{ (byte)(num) };
    }else if(num < 65536){
        return new byte[]{ (byte)(num >>> 8),(byte)num };
    }else if(num < 16777216){
        return new byte[]{ (byte)(num >>> 16),(byte)(num >>> 8),(byte)num };
    }else{ // up to 2,147,483,647
        return new byte[]{ (byte)(num >>> 24),(byte)(num >>> 16),(byte)(num >>> 8),(byte)num };
    }
}

Solution 7:^[7]

You can use this utility function:

public static byte[] fromHexString(String src) {
    byte[] biBytes = new BigInteger("10" + src.replaceAll("\\s", ""), 16).toByteArray();
    return Arrays.copyOfRange(biBytes, 1, biBytes.length);
}

Unlike variants of Denys Séguret and stefan.schwetschke, it allows inserting separator symbols (spaces, tabs, etc.) into the input string, making it more readable.

Example of usage:

private static final byte[] CDRIVES
    = fromHexString("e0 4f d0 20 ea 3a 69 10 a2 d8 08 00 2b 30 30 9d");
private static final byte[] CMYDOCS
    = fromHexString("BA8A0D4525ADD01198A80800361B1103");
private static final byte[] IEFRAME
    = fromHexString("80531c87 a0426910 a2ea0800 2b30309d");

Solution 8:^[8]

As far as a clean process is concerned you can use ByteArrayOutputStream object...

ByteArrayOutputStream bObj = new ByteArrayOutputStream();
bObj.reset();

//write all the values to bObj one by one using

bObj.write(byte value)

// when done you can get the byte[] using

CDRIVES = bObj.toByteArray();

//than you can repeat the similar process for CMYDOCS and IEFRAME as well,

NOTE This is not an efficient solution if you really have small array.

Solution 9:^[9]

My preferred option in this circumstance is to use org.apache.commons.codec.binary.Hex which has useful APIs for converting between Stringy hex and binary. For example:

Hex.decodeHex(char[] data) which throws a DecoderException if there are non-hex characters in the array, or if there are an odd number of characters.
Hex.encodeHex(byte[] data) is the counterpart to the decode method above, and spits out the char[].
Hex.encodeHexString(byte[] data) which converts back from a byte array to a String.

Usage: Hex.decodeHex("dd645a2564cbe648c8336d2be5eafaa6".toCharArray())

Solution 10:^[10]

You can use the bouncy castle package,

Maven import,

  <dependency>
        <groupId>org.bouncycastle</groupId>
        <artifactId>bcprov-jdk15on</artifactId>
    </dependency>

Java code,

byte[] CDRIVES = Hex.decode("e04fd020ea3a6910a2d808002b30309d");

Solution 11:^[11]

private static final int[] CDRIVES = new int[] {0xe0, 0xf4, ...};

and after access convert to byte.

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution	Source
Solution 1
Solution 2	Nicolas
Solution 3	Alexander Oh
Solution 4	Jon
Solution 5
Solution 6	ZMitton
Solution 7	John McClane
Solution 8
Solution 9
Solution 10	Sathesh
Solution 11	Frankie

'How do I initialize a byte array in Java?

Solution 1:[1]

Since Java 17

Before Java 17

Solution 2:[2]

Solution 3:[3]

Solution 4:[4]

Solution 5:[5]

Solution 6:[6]

Solution 7:[7]

Solution 8:[8]

Solution 9:[9]

Solution 10:[10]

Solution 11:[11]