How could I pass arguments to invoke AWS lambda function by using python?

Question

In my application,I will input data to invoke my lambda function,how can I do it? Thanks a lot.

Answer 1

The Payload parameter of the invoke function might be what you are looking for.

The format is "bytes or seekable file-like object" which means a bytes string, or an open filehandle or perhaps a BytesIO?

This works for me:

    import boto3
    import json
    import pprint

    params = {"day": "20220410"}
    client = boto3.client('lambda')
    response = client.invoke(
        FunctionName='my_lambda_function',
        InvocationType='RequestResponse',
        Payload=json.dumps(params).encode(),
    )
    pprint.pp(response['Payload'].read())

The lambda receives the params in the event dictionary:

def my_lambda_function(event, context):
    day = event['day']

Answer 2

Since, you have only mentioned

In my application, I will input data to invoke my lambda

I think you probably want to invoke lambda from you application.

For that,

• Add AWS credentials. Getting started with Python on AWS
• Import lambda from boto.

    import boto3    
    client = boto3.client('lambda')

• USE invoke() to invoke a function with parameters:

    response = client.invoke(
        FunctionName='string',
        InvocationType='Event'|'RequestResponse'|'DryRun',
        LogType='None'|'Tail',
        ClientContext='string',
        Payload=b'bytes'|file,
        Qualifier='string'
    )

You can use official documentation to explore more Lambda boto Documentation

Also,

Lambda Function can be invoked in following ways:

• AWS services events (example: SNS triggered)
• API created through AWS API Gateway.
• Amazon CloudWatch cron jobs
• API calls leveraging AWS Lambda APIs.

Documentation: Ways to Invoke AWS Lambda Function