how can i loop this code to make a pattern?

Question

***I have an assignment to create a tile pattern. I finished the pattern, but I am struggling to get the code to repeat. I need to be able to run it with the following specs:

column_ct=10,row_ct=10
column_ct=16,row_ct=9
column_ct=100,row_ct=100

with column_ct and row_ct referring to the number of columns and rows respectively. my code is pretty simple as I am very new to coding. If someone could give me advice on how to implement my code into a loop, I would be very grateful. Here is my code:***

import turtle


def tile():
    t = turtle.Turtle()

    t.fillcolor("black")
    t.begin_fill()
    t.circle(20)
    t.end_fill()

    t.penup()
    t.back(30)
    t.fillcolor("red")
    t.pendown()
    t.begin_fill()
    t.circle(50)
    t.end_fill()

    t.penup()
    t.back(50)
    t.pendown()
    t.forward(100)  # Forward turtle by 100 units
    t.left(90)  # Turn turtle by 90 degree
    t.forward(100)
    t.left(90)
    t.forward(100)
    t.left(90)
    t.forward(100)
    t.left(90)

column_ct= 10

row_ct=10

def tile_repeat (column_ct, row_ct,):
    for r in range(row_ct):
        for y in range(column_ct):
            tile()
            t.penup()
            t.forward(100)
            t.pendown



tile_repeat(10, 10)
turtle.done()

Answer 1

To loop the pattern into a grid shape you can do:

def tile_repeat (column_ct, row_ct,):
    t = turtle.Turtle()
    for r in range(row_ct):
        for y in range(column_ct):
            tile(t) # passing the turtle object to the function
            t.penup()
            t.forward(180)
            t.pendown()
        # return to left most part of drawings
        t.penup()
        t.right(180)
        t.forward(100*column_ct)
        # go down one row
        t.left(90)
        t.forward(100 )
        t.left(90)
        t.pendown()

tile_repeat(3, 3)
turtle.done()

Using this you have to pass the t variable to your function

def tile(t):

and remove the

t = turtle.Turtle()

inside of tile()