'Get the number of integers between each given range - without external packages

The task:

Write a function that receives 3 lists and returns an array. The first list contains n integers, their values range between 0 and 10^9. "numbers".
The second list is a low-range list, which contains the lower end of a range, it contains q integers. "low".
The third list is a high-range list, which contains the higher end of a range, it contains q integers. "high".

The function should return a list that contains the number of integers in the first list, that fall in its range, given by the low-range and high-range lists.

In the returned list, at index i, there should be the number of integers in "numbers" which are bigger or equal to low[i] and smaller or equal to high[i].
You can only import math, no other imports are allowed
the list may not be sorted

Examples:
count_range([12,13,14,15,17],[14],[14]) should return [1]
count_range([12,13,14,15,17],[14,15],[14,18]) should return [1,2]
count_range([12,13,14,15,17],[12],[17]) should return [5]

This is my solution but it's not efficient enough, I need ways to optimize it or solve it differently without having to import any external packages.

def binarySearch(data, val):
    highIndex = len(data) - 1
    lowIndex = 0
    while highIndex > lowIndex:
        index = math.ceil((highIndex + lowIndex) / 2)
        sub = data[index]
        if sub > val:
            if highIndex == index:
                return sorted([highIndex, lowIndex])
            highIndex = index
        else:
            if lowIndex == index:
                return sorted([highIndex, lowIndex])
            lowIndex = index
    return sorted([highIndex, lowIndex])


def count_range(numbers, low, high):
    numbers.sort()
    result = []
    low_range_dict = {}
    high_range_dict = {}
    for i in range(len(numbers)):
        if numbers[i] not in low_range_dict:
            low_range_dict[numbers[i]] = i
        high_range_dict[numbers[i]] = i
    for i in range(len(low)):
        low_r = low[i]
        high_r = high[i]
        if low_r not in low_range_dict:
            low_range_dict[low_r] = binarySearch(numbers, low_r)[0]
            high_range_dict[low_r] = low_range_dict[low_r]
        low_index = low_range_dict.get(low_r)
        if high_r not in high_range_dict:
            high_range_dict[high_r] = binarySearch(numbers, high_r)[0]
            low_range_dict[high_r] = high_range_dict[high_r]
        high_index = high_range_dict.get(high_r)
        if low_r in numbers or low_r < numbers[0]:
            low_index -= 1
        result.append(high_index - low_index)
    return result


Sources

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Source: Stack Overflow

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