'extract path name based on a string

Below is my worked examples:

from itertools import zip_longest

test2 = ['register/adam/users_photo3.jpg', 'register/adam/users_photo4.jpg', 
'register/justin/users_photo1.jpg', 'register/justin/users_photo2.jpg', 
'register/adam/users_photo3.jpg', 'register/adam/users_photo4.jpg', 
'register/justin/users_photo1.jpg', 'register/justin/users_photo2.jpg', 
'register/steve/users_photo1.jpg', 'register/steve/users_photo2.jpg', 
'register/justin/users_photo1.jpg', 'register/justin/users_photo2.jpg', 
'register/steve/users_photo1.jpg', 'register/steve/users_photo2.jpg', 
'register/justin/users_photo1.jpg', 'register/justin/users_photo2.jpg']

test = ["justin","adam"]


filter_list = []
for p,q in zip_longest(test,list_of_files):
    for r in list_of_files:
        if str(p) in r:
            filter_list.append(r)       


testmain=[p for p,r in zip_longest(test2,filter_list) if str(r) not in str(p)]
print(testmain)

I want the opposite output url of test. example "steve" url needed as output ! Needed output: All steve urls needed in output.

Hope I clarified myself and I get some response, Thank you.

Solution 1:^[1]

I would use a list comprehension along with re.search:

test2 = ['register/adam/users_photo3.jpg', 
    'register/adam/users_photo4.jpg', 
    'register/justin/users_photo1.jpg', 
    'register/justin/users_photo2.jpg', 
    'register/adam/users_photo3.jpg', 
    'register/adam/users_photo4.jpg', 
    'register/justin/users_photo1.jpg', 
    'register/justin/users_photo2.jpg', 
    'register/steve/users_photo1.jpg', 
    'register/steve/users_photo2.jpg', 
    'register/justin/users_photo1.jpg', 'register/justin/users_photo2.jpg', 
    'register/steve/users_photo1.jpg', 'register/steve/users_photo2.jpg', 
    'register/justin/users_photo1.jpg', 'register/justin/users_photo2.jpg']

test = ["justin", "adam"]
regex = r'/(?:' + '|'.join(test) + r')/'
output = [x for x in test2 if not re.search(regex, x)]
print(output)

This prints:

['register/steve/users_photo1.jpg', 'register/steve/users_photo2.jpg',
 'register/steve/users_photo1.jpg', 'register/steve/users_photo2.jpg']

Sources

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Source: Stack Overflow

Solution	Source
Solution 1	Tim Biegeleisen

'extract path name based on a string

Solution 1:[1]

Sources

Related Questions

Solution 1:^[1]