Else statement is not recognized in C# what am I missing?

Question

In C# the program is supposed to count how many valid and invalid values were entered by comparing them to the array and then give a total of the correct and incorrect inputs, but when I enter numbers that are outside of the bounds of the if statement the code from the if statement still runs. I've gone back and reviewed videos and the textbook and I cannot see where my if else statement is lacking.

        int[] values = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, };
        int count = 0;
        Console.WriteLine("Enter a value between 0 and 10");

        foreach (int v in values)
        {
            
            Console.ReadLine();

            if (values[v] >= 0 || values[v] <= 10)
            {
                Console.WriteLine("Enter a value");
                
                count++;
            }
            else
            {
                Console.WriteLine("Invalid Entry");
                
                count++;
            }
        }

        Console.WriteLine("You entered {0} correct values", count);
        Console.WriteLine("You entered {0} incorrect values", count);
        Console.ReadKey();
    }
}

Answer 1

(values[v] >= 0 || values[v] <= 10) will always return true, all numbers are either less than 10 or greater than zero. Presumably you want an and (&&) operator to grab values between 0 and 10 inclusive

Also, foreach iterates through the values of an array, not the index, so you don't need to reference values[v], you can just reference v directly (although in your case values[v]==v). Calling values[v] in a foreach runs a huge risk of indexOutOfBounds exceptions. If you want to iterate through the index a straight for loop is more appropriate:

for(int i = 0; i< values.Length; i++)
     var myVal = values[i];

Final Edit, you aren't actually checking the user's input

var input = Console.ReadLine(); 
//you never bothered capturing the user's input with a variable
decimal myNum;
if (decimal.TryParse(input, out myNum)) //did the user give a number?
{
    //use myNum instead of values[v]
}
else
{ 
    //process bad input
}

There's a bunch of stuff you can do to make things cleaner, (like removing your array altogether and using for(int i = 0; i< 10; i++) instead, for example), but good code doesn't happen on day 1 (my first few projects make me wanna throw up now), you got this friend.

Answer 2

You have a foreach loop, you do not need to use

if (values[v] >= 0 || values[v] <= 10)

instead, use

if(v >= 0 || v <= 10)

plus your if statement will always return true because the value you have in your array of int is greater than or equals to 0 or less than or equals to 10.

Try to change the array from

int[] values = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, };

to

int[] values = { -5, 1, 2, 3, 11, 5, 6, 13, 8, 9, 15, };

and you should have 4 incorrect count, provided you separate the correct count and incorrect count instead of adding them together using the count. Separate them into validCount and invalidCount