ElementClickInterceptedException: element click intercepted: Element <input> is not clickable. Other element would receive the click: <label for="..">

Question

I know i have seen this Question on StackOverFlow but not i am not able to solve my problem:

Error :

org.openqa.selenium.ElementClickInterceptedException: element click intercepted: Element <input type="password" id="Password" name="Password" value="" maxlength="25" placeholder=" " class=""> is not clickable at point (446, 716). Other element would receive the click: <label for="Password">...</label>
  (Session info: chrome=99.0.4844.83)

HTML:

<input type="password" id="Password" name="Password" value="" maxlength="25" placeholder=" " class="">

XPATH AND CSS

@FindBy(css = "#Password")
public WebElement password;

@FindBy(xpath = "//input[@id='Password']")
public WebElement password;

My code:

wait.until(ExpectedConditions.elementToBeClickable(password)).click();
wait.until(ExpectedConditions.elementToBeClickable(password)).sendKeys(PASSWORD);

Even JAVASCRIPT Click is not working

executor.executeScript("arguments[0].click();", element);

This is happening for all Checkboxes / input fields on this page. Any solution would be helpful.

Answer 1

This error message...

org.openqa.selenium.ElementClickInterceptedException: element click intercepted: Element <input type="password" id="Password" name="Password" value="" maxlength="25" placeholder=" " class=""> is not clickable at point (446, 716). Other element would receive the click: <label for="Password">...</label>
  (Session info: chrome=99.0.4844.83)

...implies that the <input> element is not clickable as the <label> element intercepts the click.

---

Deep Dive

Presumably the <input> element is preceeded by <label> element as follows:

<label for="Password" ...>
<input type="password" id="Password" name="Password" value="" maxlength="25" placeholder=" " class="">

---

Solution

In such cases, instead of the <input> element, you need to target the <label> element as follows:

• Using css:

  @FindBy(css = "label[for='Password']")
  public WebElement password;
  

• Using xpath:

  @FindBy(xpath = "//label[@for='Password']")
  public WebElement password;
  

and finally:

wait.until(ExpectedConditions.elementToBeClickable(password)).sendKeys(PASSWORD);

---

References

You can find a couple of relevant detailed discussions in:

• ElementClickInterceptedException: Message: element click intercepted: Element is not clickable with Selenium and Python

Answer 2

Can you try using JavascriptExecutor instead of sendKeys method to send password info

JavascriptExecutor jse = ((JavascriptExecutor)driver);          
WebElement email = driver.findElement(By.id("useremail"));
jse.executeScript("arguments[0].value='---your email id---';", email);