Create new instance of a given object, using same arguments provided in __init__

Question

Given any iterator, I want to be able to pass this iterator into my function, to return a new iter object that cycles through the given iter infinitely. E.G

class range:
    def __init__(self, min, max, step):
        self.min = min
        self.max = max
        self.step = counter
        [...] other vars

    def __next__(self):
        if [.............]
       

You get the jist. I have a bunch of custom iterators like this, all created with diff args/params. I know I can use vars to get the variables... but how do you distinguish between vars passed into init to create this object, and others vars? Vars returnsmin/max/counter + all the other vars

I have a class like this:

class Cycle:

    def __init__(self, iterable):
        self.iterable = iterable

    def __next__(self):
        next_val = next(self.iterable, None)
        if next_val is None:
            #RESET iterable or create new instance of iterable with same _init_ args used to create it
            next_val = next(self.iterable)
        return next_val

Intended use:

r = range(0,4,2)
next(r) = 0

next(r) = 2

next(r) = 4

next(r) = stopiterationerror

c = Cycle(r)

next(c) = 0

next(c) = 2

next(c) = 4

next(c) = 0

next(c) = 2

next(c) = 4

....... I want to keep this cycle function clean and simple if I can. Ideally I would want to simply self.iterable.reset, but it seems like resetting an iterable is not possible in python and I need to create a brand new instance. I know I could pass in *args into cycle, but is it possible to avoid that?

edit currently working:

class Cycle:

    def __init__(self, iterable):
        self.iterable = iterable
        self.copy = copy(iterable)

    def __next__(self):
        next_val = next(self.iterable, None)
        if next_val is None:
            self.iterable = self.copy
            self.copy = copy(self.copy)
            next_val = next(self.iterable, None)
        return next_val