z = zipfile.ZipFile("zipfile.zip", "w") z.write(filename) It takes string as an argument that is actually path of that file to be add to the zip. But I want t
swc-compiler
operator-overloading
symfony-process
shields.io
analysis
thunar
ambient
assemblies
on-screen-keyboard
clickonce
rrule
simplexmlrpcserver
delphi-5
stockfish
intellij-17
hkhealthstore
zero-initialization
grid
sideloading
anvil
go-xorm
least-astonishment
mi
autocommit
node-pty
pnpm
bigcommerce
windows-error-reporting
angularjs-components
mobile-safari