def min_heapify(A,k, n): left = 2*k +1 right = 2*k +2 n=int(len(A)) if left < n and A[left] < A[k]: smallest = left else:
redgate
openkinect
boost-regex
openprocess
jquery
struts2-jquery
cookieconsent
tidygraph
octobercms-plugins
proximitysensor
touchablehighlight
mainactor
weld-junit5
mendix
execline
android-productflavors
php4
spatie-ssh
record-classes
resumable
ngx-clipboard
irvine32
weboptimizer
fact-table
git-stash
update-inner-join
page-load-time
jackson2
infopath
webpack-splitchunks