def min_heapify(A,k, n): left = 2*k +1 right = 2*k +2 n=int(len(A)) if left < n and A[left] < A[k]: smallest = left else:
aws-policies
mappedby
selenium-webdriver
android-handlerthread
object-expected
billing
document-class
database-server
argv
uwp-maps
native-crash-reporting
createwritestream
badpaddingexception
mode
telemetry
cirrus-ci
vbe
google-advertising-id
timeval
chrome-remote-desktop
gotjs
ios8.3
fixed-length-array
dataproc
sql-server-group-concat
whitesource
node-mysql2
javafx
azure-language-understanding
rx.net