'Can't import module from different directory python
So below I have is my file structure:
/
api.py
app.py
code/
data_api/
weather_data/
get_data_dir/
get_data.py
master_call_dir/
master_call.py
My current problem is that I'm importing master_call.py from inside app.py I do this with the following code:
-- app.py
import sys
sys.path.append('./code/data_api/weather_data/master_call_dir')
from master_call import master_call_interface as master_call
Importing master_call itself works perfectly fine, the issue is that inside off master_call I import get_data.py. I do this with the following code:
-- master_call.py
import sys
sys.path.append("../get_data_dir")
from get_data import get_data_module
When printing out sys.path I can see ../get_data_dir inside of it but Python still isn't able to find the get_data.py file in /get_data_dir.
Does anyone know how to fix this?
(there is an __init__.py file in every directory, I removed it here for readability)
Solution 1:[1]
So I figured it out. The problem is while the directory of the master_call.py file is /code/data_api/weather_data/master_call the current working directory (CWD) is / since that is where app.py is located.
To fix it we simply fetch absolute file path in each python script with
current_path = os.path.dirname(os.path.realpath(__file__)).replace('\\', '/')
and pre-pend it to any file path we're appending with sys.path.append
So it'd look like this in practice:
import sys
import os
current_path = os.path.dirname(os.path.realpath(__file__)).replace('\\', '/')
sys.path.append(f'{current_path}./code/data_api/weather_data/master_call_dir')
from master_call import master_call_interface as master_call
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Quantitative |
