'ARG substitution in RUN command not working for Dockerfile
In my Dockerfile I have the following:
ARG a-version
RUN wget -q -O /tmp/alle.tar.gz http://someserver/server/$a-version/a-server-$a-version.tar.gz && \
mkdir /opt/apps/$a-version
However when building this with:
--build-arg http_proxy=http://myproxy","--build-arg a-version=a","--build-arg b-version=b"
Step 10/15 : RUN wget... is shown with $a-version in the path instead of the substituted value and the build fails.
I have followed the instructions shown here but must be missing something else.
My questions is, what could be causing this issue and how can i solve it?
Solution 1:[1]
Another thing to be careful about is that after every FROM statements all the ARGs get collected and are no longer available. Be careful with multi-stage builds.
You can reuse ARG with omitted default value inside FROM to get through this problem:
ARG VERSION=latest
FROM busybox:$VERSION
ARG VERSION
RUN echo $VERSION > image_version
Example taken from docs: https://docs.docker.com/engine/reference/builder/#understand-how-arg-and-from-interact
Solution 2:[2]
I had the same problem using Windows containers for Windows.
Instead of doing this (Which works in linux containers)
FROM alpine
ARG TARGETPLATFORM
RUN echo "I'm building for $TARGETPLATFORM"
You need to do this
FROM mcr.microsoft.com/windows/servercore
ARG TARGETPLATFORM
RUN echo "I'm building for %TARGETPLATFORM%"
Just change the variable resolution according to the OS.
Solution 3:[3]
I spent much time to have the argument substitution working, but the solution was really simple. The substitution within RUN needs the argument reference to be enclosed in double quotes.
ARG CONFIGURATION=Debug
RUN dotnet publish "Project.csproj" -c "$CONFIGURATION" -o /app/publish
Solution 4:[4]
The only way I was able to substitute an ARG in a Windows Container was to prefix with $env:, as mentioned here.
An example of my Dockerfile is below. Notice that the ARG PAT is defined after the FROM so that it's in scope for its use in the RUN nuget sources add command (as Hongtao suggested). The only successful way I found to supply the personal access token was using $env:PAT
FROM mcr.microsoft.com/dotnet/framework/sdk:4.7.2 AS build
WORKDIR /app
ARG PAT
# copy csproj and restore as distinct layers
COPY *.sln .
COPY WebApi/*.csproj ./WebApi/
COPY WebApi/*.config ./WebApi/
RUN nuget sources add -name AppDev -source https://mysource.pkgs.visualstudio.com/_packaging/AppDev/nuget/v2 -username usern -password $env:PAT
RUN nuget restore
# copy everything else and build app
COPY WebApi/. ./WebApi/
WORKDIR /app/WebApi
RUN msbuild /p:Configuration=Release
FROM mcr.microsoft.com/dotnet/framework/aspnet:4.7.2 AS runtime
WORKDIR /inetpub/wwwroot
COPY --from=build /app/WebApi/. ./
The actual Docker command looks like this:
docker build --build-arg PAT=mypatgoeshere -t webapi .
Solution 5:[5]
I had the same problem accessing build-args in my RUN command. Turns out that the line containing the ARG definition should not be the first line. The working Dockerfile snippet looks like this:
FROM centos:7
MAINTAINER xxxxx
ARG SERVER_IPS
Earlier, I had placed the ARG definition as the first line of Dockerfile . My docker version is v19.
Solution 6:[6]
For me it was argument's order:
docker build . -f somepath/to/Dockerfile --build-arg FOO=BAR
did not work, but:
docker build --build-arg FOO=BAR . -f somepath/to/Dockerfile
did.
Solution 7:[7]
There are many answers, which make sense. But the main thing is missed.
The way, how to use build arguments depends on the base image.
- For Linux image, it will work with
$ARG - For Windows, depending on image, it can be either
$env:ARG(e.g. for mcr.microsoft.com/dotnet/framework/sdk:4.8) or %ARG% (e.g. for mcr.microsoft.com/windows/nanoserver:1809)
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Marcello Romani |
| Solution 2 | |
| Solution 3 | |
| Solution 4 | nbrosz |
| Solution 5 | |
| Solution 6 | pbn |
| Solution 7 | Anton |
