Write a program using integers user_num and x as input, and output user_num divided by x three times

Question

Write a program using integers user_num and x as input, and output user_num divided by x three times.

Ex:

If the input is:
2000
2

Then the output is:

1000 500 250

Note: In Python 3, integer division discards fractions. Ex: 6 // 4 is 1 (the 0.5 is discarded).

Here is my code that I have:

user_num = int(input())
x = int(input())

for i in range(3):
    user_num/= x
    print (int(user_num), end=' ')

I just need to add a end line with the output comes up with 250.

Answer 1

it's shockingly much simpler than y'all are making it. The program wants a straight forward answer.

user_num = int(input())
x = int(input())

print (user_num // x , user_num // x // x , user_num // x// x // x)

Answer 2

This is in C but you can see the logic.

#include <stdio.h>

int main(void) {

   int userNum;
   int x;
   int ans1;
   int ans2;
   int ans3;
   
   scanf("%d", &userNum);
   scanf("%d", &x);
   
   ans1 = userNum/x;
   ans2 = ans1/x;
   ans3 = ans2/x;
   
   printf("%d %d %d\n", ans1, ans2, ans3); 

   return 0;
}

Answer 3

''' Type your code here. '''
user_num = int(input()) 
x = int (input())
 
i = 0
while i <= 2 :
    if i <= 1:
        user_num //= x
        print(user_num, end= " ")
        i += 1
    elif i == 2:
        user_num //= x
        print(user_num)
        i += 1

Answer 4

This should work just fine

user_num = int(input())
x = int(input())

results = []
for i in range(3):
    user_num/= x
    results.append(str(int(user_num)))
print(' '.join(results))

Answer 5

user_num = int(input())

x = int(input())

    user_num1 = user_num // x
    user_num2 = user_num1 // x
    user_num3 = user_num2 // x

print(user_num1, user_num2, user_num3)