'Why my code palindrome works only for single input not for many inputs?

A palindrome is a word or a phrase that is the same when read both forward and backward. Examples are: "bob," "sees," or "never odd or even" (ignoring spaces). Write a program whose input is a word or phrase, and that outputs whether the input is a palindrome.

I'm only getting this half right. my code is working for bob, and sees. When an input is "never odd or even" my code doesn't work it shows is not a palindrome but it should be a palindrome.

What am I doing wrong here?

word = str(input())
new = word.replace(" ", "")
new = new[::-1]

if word == new:
    print('{} is a palindrome'.format(word))
else:
    print('{} is not a palindrome'.format(word))

python palindrome

Solution 1:^[1]

You are comparing word with new, but to generate new you had removed all the spaces.

Solution 2:^[2]

That is because of line new = word.replace(" ", "") - the word is kept with the spaces in it. You should make a version of word with no spaces, reverse that, then compare it with the no-spaces word.

Something like:

  word = str(input())
  spaceless_word = word.replace(" ", "")
  new = spaceless_word[::-1]

  if spaceless_word == new:
      print('{} is a palindrome'.format(word))
  else:
      print('{} is not a palindrome'.format(word))

Solution 3:^[3]

try this

word = str(input())
word = word.replace(" ", "")
new = word
new = new[::-1]

if word == new:
    print('{} is a palindrome'.format(word))
else:
    print('{} is not a palindrome'.format(word))

Sources

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Source: Stack Overflow

Solution	Source
Solution 1	Bnz
Solution 2	foobarna
Solution 3	Strider

'Why my code palindrome works only for single input not for many inputs?

Solution 1:[1]

Solution 2:[2]

Solution 3:[3]

Sources

Related Questions

Solution 1:^[1]

Solution 2:^[2]

Solution 3:^[3]