Why is this function call returning undefined as well

Question

I have written a simple JavaScript code to print the max number of an array and get undefined printed as well.

let arrNums = [1,2,5,19,20];
const maxNum = function(arr) {
if (arr.length != 0) {
    console.log(Math.max(...arr));
}
else{
    console.log("Empty");  
}}

console.log(maxNum(arrNums));

Answer 1

Your function doesn't return anything. Return the Math.max() and the 'Empty' for it to work. After that you can just use console.log(maxNum(arrNums)); outside the function. See below for an example of this:

const arrNums = [1, 2, 5, 19, 20];
const maxNum = function (arr) {
    if (arr.length != 0) {
        return Math.max(...arr);
    } else {
        return 'Empty';
    }
}

console.log(maxNum(arrNums));

Hoped this helped!