'Why does `using X = int32_t()` cause a VS warning that it can't find the function definition for 'int32_t'?

The template parameter for std::function is in the form T(...). I want to use using to label some of those template parameters like the following:

using const_s32_sig = int32_t();
using const_s32 = std::function<const_s32_sig>;

using identity_sig = int32_t(int32_t);
using identity = std::function<identity_sig>;

For some reason, VS gives me the following warning:

enter image description here

only for the first sig definition. However, this only happens when the type name is typedef'd (e.g. int32_t, ...), and that's not the case for non-typedef'd data types such as regular ints.

I reckon it is harmless (I am perceiving the expected behavior) but I want to know if this can affect me in any way and how to resolve it, if possible?

c++visual-studio


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