why does this accept any username as long as password is correct

Question

username = input("Welcome, please enter your username.")
password = input("Please enter your password.")

if username != "tony" and password != "password123":
  print("Access Denied.")

else:
  print("Welcome to the jungle")

Answer 1

Will try to make you understand by AND gate.

A	B	C	D	E
username	password	username!=Tony	password!=password123	Colmn_C AND Colmn_D(Access denied)
Tony	password123	FALSE	FALSE	FALSE
Hulk	Password123	TRUE	FALSE	FALSE
Tony	xyz	FALSE	TRUE	FALSE
Hulk	xyz	TRUE	TRUE	TRUE

So you can see ,why Access is denied only when both are incorrect

Answer 2

Change the test to:

if username != "tony" or password != "password123":

or turn the whole thing around:

if username == "tony" and password == "password123":
  print("Welcome to the jungle")    
else:
  print("Access Denied.")

That (IMO) makes it more clear both the username and the password need to be correct.

Answer 3

Good news, your code is written correctly!.
Bad news, your code is not doing what you want.

Try to read your conditional out load.

Your computer: 'if the user name is not "tony" and the password is not "password123," I should deny access.
Everything else I should accept.' That means, when only one of them is wrong, it is ok!

Answer 4

just change the statements or change the condition AND with OR

solution1

username = input("Welcome, please enter your username.")
password = input("Please enter your password.")
if username != "tony" or password != "password123":
  print("Access Denied.")
else:
  print("Welcome to the jungle")

solution2

username = input("Welcome, please enter your username.")
password = input("Please enter your password.")
if username != "tony" and password != "password123":
   print("Welcome to the jungle")
else:
   print("Access Denied.")