Why can variables be initialized(and used) without its declaration and definition "being run"?

Question

C++ disallows "goto-ing over a definition:"

goto jumpover;
int something = 3;
jumpover:
std::cout << something << std::endl;

This will raise an error as expected, because "something" won't be declared(or defined).

However, I jumped over using assembly code:

#include<iostream>
using namespace std;
int main(){
    asm("\njmp tag\n");
    int ptr=9000;//jumped over
    cout << "Ran" << endl;
    asm("\ntag:\n");
    cout << ptr << endl;
    return 0;
}

It printed 9000, although the int ptr=9000;//jumped over line is NOT executed, because the program did not print Ran. I expected it would cause a memory corruption/undefined value when ptr is used, because the memory isn't allocated(although the compiler thinks it is,because it does not understand ASM). How can it know ptr is 9000?

Does that mean ptr is created and assigned at the start of main()(therefore not skipped,due to some optimizations or whatever) or some other reason?