'Where should I close it file? [closed]
def get_pic(f_id: str):
__file__ = open(db_files.get_pic(f_id), mode='rb')
return StreamingResponse(__file__, media_type="image/jpg")
if i file.close() cant return if i return cant close Where should I close it file?
Solution 1:[1]
def iterfile():
with open(db_files.get_pic(f_id), "rb") as img:
yield from img
return StreamingResponse(iterfile(), media_type="image/jpg")
Solution 2:[2]
You should use with open...:
def get_pic(f_id: str):
with open(db_files.get_pic(f_id), mode='rb') as __file__:
img_to_return = StreamingResponse(__file__, media_type="image/jpg")
return img_to_return
This implicitly calls __file__.close()
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | IFCZT |
| Solution 2 |
