'What’s the best way to check if a list contains an item other than specified item?
Lets say I have a list and I want to search for an item with value “apple”.
List<String> items = new Arraylist<>():
I want to return false if items contains at least one element other than the item mentioned (“apple”), true if all items in the list are “apples”.
Solution 1:[1]
Here's a one-liner:
return items.stream().anyMatch(s -> !s.equals("apple"));
or cute but a little less obvious:
return items.stream().allMatch("apple"::equals);
Solution 2:[2]
I use python but, I think is something like that:
list_entrance = input()
new_list = []
for cycle in list_entrance: if cycle != "apple": print("falce") else: continue
If you want of course you can "append" a items in "new_list". I don't know full condition on your task.
Solution 3:[3]
Just to say your ArrayList should be defined like this:
List items = new ArrayList<>();
You missed out some caps in the question.
For the solution you could just loop through the list and check:
for (int x = 0; x<items.size(); x++){
if (! items.get(x).equals("apple")){
return false;
}
}
return true;
Solution 4:[4]
Instead use a Set, in order not to have duplicate items.
Collectors can also return Set:
Set<String> distinct = list.stream().collect(Collectors.toSet());
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | |
| Solution 2 | K9999 |
| Solution 3 | Gamaray |
| Solution 4 | Martin Zeitler |
